[英]How to print with inline if statement?
該字典對應於編號節點:
{0: True, 1: True, 2: True, 3: False, 4: False, 5: False, 6: True, 7: True, 8: False, 9: False}
使用兩個打印語句,我想打印標記和未標記的節點,如下所示:
標記節點: 0 1 2 6 7
無標記節點: 3 4 5 8 9
我想要一些接近的東西:
print("Marked nodes: %d" key in markedDict if markedDict[key] = True)
print("Unmarked nodes: %d" key in markedDict if markedDict[key] = False)
您可以使用列表推導:
nodes = {0: True, 1: True, 2: True,
3: False, 4: False, 5: False,
6: True, 7: True, 8: False, 9: False}
print("Marked nodes: ", *[i for i, value in nodes.items() if value])
print("Unmarked nodes: ", *[i for i, value in nodes.items() if not value])
輸出:
Marked nodes: 0 1 2 6 7
Unmarked nodes: 3 4 5 8 9
這是另一個適用於python版本的解決方案,它不支持頂部答案中使用的解包語法。 讓d
成為你的字典:
>>> print('marked nodes: ' + ' '.join(str(x) for x,y in d.items() if y))
marked nodes: 0 1 2 6 7
>>> print('unmarked nodes: ' + ' '.join(str(x) for x,y in d.items() if not y))
unmarked nodes: 3 4 5 8 9
我們可以避免重復迭代字典。
marked = []
unmarked = []
mappend = marked.append
unmappend = unmarked.append
[mappend(str(x))if y else unmappend(str(x)) for x, y in d.iteritems()]
print "Marked - %s\r\nUnmarked - %s" %(' '. join(marked), ' '. join(unmarked))
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