為什么我的函數未在程序（java）中運行？

Question

該程序應該遞歸解決迷宮。 readMazeFile將文件的內容讀取到數組中，然后solveMaze函數使用該數組來求解迷宮。 但是在我的主要功能中，似乎（maze！= null）似乎沒有運行。 我包括了它以消除空指針異常。 迷宮=空嗎？ 我不這么認為，但IDK。 感謝您的幫助。

public class solving {
    static char maze[][];
    static int startingrow;
    static int startingcol;

    public static void main(String[] args) throws FileNotFoundException {
        readMazeFile("maze0.txt");
        if (maze != null) {
            System.out.print(maze[1][1]);

            if (solveMaze(startingrow, startingcol))
                System.out.print("Solved!");
            else
                System.out.print("There is no solution to this maze.");
        }
    }

    static boolean solveMaze(int row, int col) {
        // name each movement to make coding easier to understand with the recursion.
        char right = maze[row][col + 1];
        char left = maze[row][col - 1];
        char up = maze[row - 1][col];
        char down = maze[row + 1][col];
        char markSpot = 'M';
        char unmarkSpot = ' ';

        // Base case is at the end of the maze
        if (right == 'E' || left == 'E' || up == 'E' || down == 'E') {
            return true;
        }

        // What to do if there is an empty space when it moves
        if (right == ' ') {
            right = markSpot;
            if (solveMaze(row, col + 1)) {
                return true;
            } else {
                right = unmarkSpot;
            }
        }

        if (down == ' ') {
            down = markSpot;
            if (solveMaze(row + 1, col)) {
                return true;
            } else {
                up = unmarkSpot;
            }
        }

        if (left == ' ') {
            left = markSpot;
            if (solveMaze(row, col - 1)) {
                return true;
            } else {
                left = unmarkSpot;
            }
        }

        if (up == ' ') {
            up = markSpot;
            if (solveMaze(row - 1, col)) {
                return true;
            } else {
                up = unmarkSpot;
            }
        }
        return false;
    }

    static char[][] readMazeFile(String mazeFile) throws FileNotFoundException {
        Scanner input = new Scanner(new File(mazeFile));

        // Find the height and width
        int height = input.nextInt();
        int width = input.nextInt();
        int finalHeight = (2 * height) + 1;
        int finalWidth = (2 * width) + 1;

        // Create the array and put data from the file in it
        char maze[][] = new char[finalHeight][finalWidth];
        input.nextLine();

        for (int row = 0; row < finalHeight; row++) {
            String fileLine = input.nextLine();
            for (int col = 0; col < finalWidth; col++) {
                char nextChar = fileLine.charAt(col);
                maze[row][col] = nextChar;
            }
        }

        // Find the starting point
        for (int r = 0; r < finalHeight; r++) {
            for (int c = 0; c < finalWidth; c++) {
                if (maze[r][c] == 'S') {
                    int startingrow = r;
                    int startingcol = c;
                    //System.out.print(startingrow);
                    //System.out.print(startingcol);
                }
            }
        }

        return maze;
    }
}

Answer 1

readMazeFile的maze變量readMazeFile了您在條件條件中使用的靜態變量。

要么：

• 分配結果readMazeFile 。
• 不要在readMazeFile聲明新的maze變量（刪除char類型聲明readMazeFile ）。 然后將其返回就不必要了。

Answer 2

您必須將函數調用的結果存儲在變量迷宮的main的第一行中。 由於尚未執行此操作，因此迷宮當然為空。