范圍內的隨機數

Question

在任何情況下，都可以使用此工具生成倉位定單。

但是，我遇到了無限循環。 我怎樣才能解決這個問題？

import java.util.Random;
import java.util.Scanner;
public class WhoGoesFirst {
    public static void main(String args[]) {
        Random random = new Random();
        Scanner input = new Scanner(System.in);
        int MIN = 1;
        int students = 0;

        System.out.print("How many students do you have?");
        students = input.nextInt();

        int comp = random.nextInt(students - MIN + 1) + MIN;

        for (int number = 0; number <= students; comp++) {
            System.out.println(random);
        }
    }
}

Answer 1

在循環中增加您的數字變量，它應該可以解決此問題：

for (int number = 0; number <= students; number++, comp++) {
                System.out.println(comp); //random is an object
        }

Answer 2

您需要增加數字：

import java.util.Random;
import java.util.Scanner;
public class WhoGoesFirst {
        public static void main(String args[]) {
        Random random = new Random();
        Scanner input = new Scanner(System.in);
        int MIN = 1;
        int students = 0;

        System.out.print("How many students do you have?");
        students = input.nextInt();

        int comp = random.nextInt(students - MIN + 1) + MIN;

        for (int number = 0; number <= students; number++) {
                System.out.println(random);
                comp++;
        }
    }
}

Answer 3

看這行：

System.out.println(random);

此實現嘗試打印隨機數生成器，而不是數字本身。 使用內置的Collections.shuffle有一個更簡單的解決方案：

List<Integer> positions = new ArrayList<Integer>(students);
for (int number = 0; number < students; number++)
    positions.add(number);

Collections.shuffle(positions);

for (Integer number : positions)
    System.out.println(number);