如何將關鍵字放入代碼中？

Question

好吧，我該如何編寫我的代碼，而不是將其放在1到4之間，而只需在其中輸入“ Freezing”或“ Froze”之類的關鍵字。如何在我的代碼中放入關鍵字搜索器，感謝所有幫助，謝謝:)

    def menu():
  print("Welcome to Kierans Phone Troubleshooting program")
  print("Please Enter your name")
  name=input()
  print("Thanks for using Kierans Phone Troubleshooting program "+name +"\n")

def start():
  select = " "
  print("Would you like to start this program? Please enter either y for yes or n for no")
  select=input()
  if select=="y":
    troubleshooter()
  elif select=="n":
    quit
  else:
    print("Invalid please enter again")

def troubleshooter():
  print("""Please choose the problem you are having with your phone (input 1-4):
1) My phone doesn't turn on
2) My phone is freezing
3) The screen is cracked
4) I dropped my phone in water\n""")
  problemselect = int(input())
  if problemselect ==1:
    not_on()
  elif problemselect ==2:
    freezing()
  elif problemselect ==3:
    cracked()
  elif problemselect ==4:
    water()
  start()

def not_on():
  print("Have you plugged in the charger?")
  answer = input()
  if answer =="y":
    print("Charge it with a diffrent charger in a diffrent phone socket. Does it work?")
  else:
    print("Plug it in and leave it for 20 mins, has it come on?")
  answer = input()
  if answer=="y":
    print("Are there any more problems?")
  else:
    print("Restart the troubleshooter or take phone to a specialist\n")
  answer=input()
  if answer =="y":
    print("Restart this program")
  else:
    print("Thank you for using my troubleshooting program!\n")

def freezing():
  print("Charge it with a diffrent charger in a diffrent phone socket")
  answer = input("Are there any more problems?")
  if answer=="y":
    print("Restart the troubleshooter or take phone to a specialist\n")
  else:
    print("Restart this program\n")

def cracked():
  answer =input("Is your device responsive to touch?")
  if answer=="y":
    answer2 = input("Are there any more problems?")
  else:
    print("Take your phone to get the screen replaced")
  if answer2=="y":
    print("Restart the program or take phone to a specialist\n")
  else:
    print("Thank you for using my troubleshooting program!\n")

def water():
  print("Do not charge it and take it to the nearest specialist\n")

menu()
while True:
  start()
  troubleshooter()

Answer 1

您正在尋找一個enum

from enum import Enum
class Status(Enum):
    NOT_ON = 1
    FREEZING = 2
    CRACKED = 3
    WATER = 4

然后在if檢查中，您將執行以下操作：

if problemselect == Status.NOT_ON:
    ...
elif problemselect == Status.FREEZING:
    ...

Answer 2

由於您希望用戶輸入電話問題的描述，因此您可能需要一個問題列表以及與這些問題相關的關鍵字。 以下程序顯示了如何安排這樣的數據庫以及如何根據用戶的輸入進行搜索。 此解決方案有更快的替代方法（例如，為數據庫建立索引），但是目前這種基本實現應該足夠了。 您將需要提供有關如何解決問題的更多代碼和信息，但是對上一個問題的解答應有助於您在這方面進行指導。

#! /usr/bin/env python3

# The following is a database of problem and keywords for those problems.
# Its format should be extended to take into account possible solutions.
PROBLEMS = (('My phone does not turn on.',
             {'power', 'turn', 'on', 'off'}),
            ('My phone is freezing.',
             {'freeze', 'freezing'}),
            ('The screen is cracked.',
             {'cracked', 'crack', 'broke', 'broken', 'screen'}),
            ('I dropped my phone in water.',
             {'water', 'drop', 'dropped'}))


# These are possible answers accepted for yes/no style questions.
POSITIVE = tuple(map(str.casefold, ('yes', 'true', '1')))
NEGATIVE = tuple(map(str.casefold, ('no', 'false', '0')))


def main():
    """Find out what problem is being experienced and provide a solution."""
    description = input('Please describe the problem with your phone: ')
    words = {''.join(filter(str.isalpha, word))
             for word in description.lower().split()}
    for problem, keywords in PROBLEMS:
        if words & keywords:
            print('This may be what you are experiencing:')
            print(problem)
            if get_response('Does this match your problem? '):
                print('The solution to your problem is ...')
                # Provide code that shows how to fix the problem.
                break
    else:
        print('Sorry, but I cannot help you.')


def get_response(query):
    """Ask the user yes/no style questions and return the results."""
    while True:
        answer = input(query).casefold()
        if answer:
            if any(option.startswith(answer) for option in POSITIVE):
                return True
            if any(option.startswith(answer) for option in NEGATIVE):
                return False
        print('Please provide a positive or negative answer.')


if __name__ == '__main__':
    main()