將XML節點插入表中的SQL列

Question

我有一個XML文件，我將其傳遞給存儲過程。

我也有一張桌子。 該表有VehicleReg |列 XML | ProcessedDate

我的XML就是這樣的：

<vehicles> 
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
</vehicles>

我需要做的是讀取xml並將vehiclereg和整車xml字符串插入每一行（dateprocessed是getdate（）所以不是問題）。

我正在做類似下面的事情，但沒有運氣：

DECLARE @XmlData XML
Set @XmlData = EXAMPLE XML
SELECT T.Vehicle.value('(vehiclereg)[1]', 'NVARCHAR(10)') AS vehiclereg,
       T.Vehicle.value('.', 'NVARCHAR(MAX)'),
       GETDATE()
FROM @XmlData.nodes('Vehicles/Vehicle') AS T(Vehicle)

我想知道是否有人可以指出我正確的方向？

問候

Answer 1

只需要記住XML區分大小寫。 你有過：

FROM @XmlData.nodes('Vehicles/Vehicle') AS T(Vehicle)

但你應該有：

FROM @XmlData.nodes('/vehicles/vehicle') AS T(Vehicle)

此外，TT指出沒有名為Registration列

這應該這樣做：

DECLARE @XmlData XML
Set @XmlData = '<vehicles> 
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
</vehicles>'
SELECT  Vehicle.value('(vehiclereg)[1]', 'NVARCHAR(10)') AS vehiclereg,
        Vehicle.value('.', 'NVARCHAR(MAX)'),
       GETDATE()
FROM @XmlData.nodes('/vehicles/vehicle') AS T(Vehicle)

結果：

這將返回XML：

DECLARE @XmlData XML
Set @XmlData = '<vehicles> 
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
</vehicles>'
SELECT T.Vehicle.value('(vehiclereg)[1]', 'NVARCHAR(10)') AS vehiclereg,
       T.Vehicle.query('.'),
       GETDATE()
FROM @XmlData.nodes('vehicles/vehicle') AS T(Vehicle)

結果：

Answer 2

完整查詢，如您所願：

DECLARE @XmlData XML
Set @XmlData = '<vehicles> 
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
</vehicles>'
SELECT T.Vehicle.value('./vehiclereg[1]', 'NVARCHAR(10)') AS vehiclereg,
       T.Vehicle.query('.'),
       GETDATE()
FROM @XmlData.nodes('/vehicles/vehicle') AS T(Vehicle)

Answer 3

您可以通過XML.query()獲取XML，在這種情況下，在vehicles/vehicle節點上query('.')以獲取內部XML。

DECLARE @x XML=
'<vehicles> 
  <vehicle>
    <vehiclereg>AB12CBE</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
  <vehicle>
    <vehiclereg>AB13QQT</vehiclereg>
    <anotherprop>BLAH</anotherprop>
  </vehicle>
</vehicles>';

DECLARE @t TABLE(VehicleReg VARCHAR(128),[XML] XML,ProcessedDate DATETIME);

INSERT INTO @t(VehicleReg,[XML],ProcessedDate)
SELECT VehicleReg=n.v.value('(vehiclereg)[1]','VARCHAR(128)'),
       [XML]=n.v.query('.'),
       ProcessedDate=GETDATE()
FROM @x.nodes('vehicles/vehicle') AS n(v);

SELECT * FROM @t;

結果：

+------------+------------------------------------------------------------------------------------+-------------------------+
| VehicleReg |                                XML                                                 |      ProcessedDate      |
+------------+------------------------------------------------------------------------------------+-------------------------+
| AB12CBE    | <vehicle><vehiclereg>AB12CBE</vehiclereg><anotherprop>BLAH</anotherprop></vehicle> | 2016-03-01 15:21:37.640 |
| AB13QQT    | <vehicle><vehiclereg>AB13QQT</vehiclereg><anotherprop>BLAH</anotherprop></vehicle> | 2016-03-01 15:21:37.640 |
+------------+------------------------------------------------------------------------------------+-------------------------+