[英]How do you refresh a label in tkinter and python
我正在嘗試創建一個小窗口,告訴我前十名玩家的資金狀況。 問題是,每當我按下“更新”按鈕時,它都不會刪除播放器標簽的舊列表。 tkinter中有明確的功能嗎?
碼:
from tkinter import *
import sqlite3
def getlist():
conn = sqlite3.connect('C:\sqlite\crapsdatabase.db')
c = conn.cursor()
c.execute("SELECT playerName, playerBank FROM player ORDER BY playerBank desc limit 10")
temp = c.fetchall()
for row in temp:
texthold = str(row[0]) + ' ' + str(row[1])
print(texthold)
player = Label(root, text=texthold)
player.pack()
conn.commit() #confirms changes to the databae
c.close() #closes the connection to the database
conn.close()
root =Tk()
theLabel =Label(root, text="Top Ten Players")
buttonUpdate = Button(root, text="Update", fg="green", command = getlist)
buttonUpdate.pack()
theLabel.pack()
root.mainloop()
代替創建新的Label
,您應該使用player.config(text="Some new value")
方法。 (您將需要在全局變量中保留對Label的引用)。
Nb由於您有多個標簽,因此應在列表中保留對Label對象的引用。
由於getlist()
為每個項目創建一個新的Label
,因此一種方法是從窗口(和內存)中刪除以前的列表,並生成一個新的播放器列表(和標簽)。
我們需要保留對創建的標簽的引用(在getlist()
),以便稍后我們可以將其刪除。 類似於以下代碼(嘗試更改為所討論代碼示例的最小值):
from tkinter import *
import sqlite3
top_list = [] # holds the player labels currently shown
def getlist():
global top_list
conn = sqlite3.connect('C:\sqlite\crapsdatabase.db')
c = conn.cursor()
c.execute("SELECT playerName, playerBank FROM player ORDER BY playerBank desc limit 10")
temp = c.fetchall()
for player in top_list:
player.pack_forget() # remove label from window
top_list = [] # remove references to free memory
for row in temp:
texthold = str(row[0]) + ' ' + str(row[1])
print(texthold)
player = Label(root, text=texthold)
player.pack()
top_list.append(player)
conn.commit() #confirms changes to the databae
c.close() #closes the connection to the database
conn.close()
root = Tk()
theLabel = Label(root, text="Top Ten Players")
buttonUpdate = Button(root, text="Update", fg="green", command=getlist)
buttonUpdate.pack()
theLabel.pack()
root.mainloop()
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