從PostAsync讀取XML響應（）

Question

我正在使用PostAsync()發送數據，代碼執行完全正確。 我發送數據的站點提供XML響應通知，通知成功或失敗。 XML響應是這樣的： 成功的帖子返回1

 <?xml version="1.0" encoding="utf-8" ?> <result> <success>1</success> <uploadid/> </errors> </result> 

而非成功則返回<error>標記之間的原因

<?xml version="1.0" encoding="utf-8" ?>
<result>
 <success>0</success>
 <iploadid/>
 <errors>
    <error>File is not in correct format</error>
 </errors>
</result>

這是我用來執行PostAsync() C＃語法，我需要添加什么才能從頁面讀取XML響應？

private void SendAsyncData()
{
  string connectionString = "Data Source=hmod;Initial Catalog=salesdb;uid=userid;password=password;MultipleActiveResultSets=True";
  DataTable grds = new DataTable();
  using (var con = new SqlConnection(connectionString))
  using (var cmd = new SqlCommand("procedureone", con))
  using (var da = new SqlDataAdapter(cmd))
  {
    cmd.CommandType = CommandType.StoredProcedure;
    da.Fill(grds);
  }
  var client = new HttpClient();
  var q = string.Empty;
  foreach (DataRow row in grds.Rows)
  {
    var parameterSet = new List<KeyValuePair<string, string>>();
    for (int i = 0; i < grds.Columns.Count; ++i)
    {
        parameterSet.Add(new KeyValuePair<string, string>(grds.Columns[i].ColumnName, row[i].ToString()));

    }

    var result = client.PostAsync("http://weneedsampledata/ashx", new FormUrlEncodedContent(parameterSet)).Result;
    string resultContent = result.Content.ReadAsStringAsync().Result;
  }
}

編輯
目前，即使接收數據的站點引發錯誤，此語法也會返回200（成功）的代碼，我需要一種“讀取”XML響應以確定數據是否實際成功的方法。 我試圖在下面添加讀取響應，但它給我一個編譯錯誤：

'System.Net.Http.HttpResponseMessage'不包含'GetResponse'的定義，並且沒有可以找到接受類型'System.Net.Http.HttpResponseMessage'的第一個參數的擴展方法'GetResponse'（你是否缺少using指令）或匯編參考？）

var response = result.GetResponse();
Stream receiveStream = response.GetResponseStream();
StreamReader readStream = new StreamReader(receiveStream, Encoding.UTF8);
var postresult = readStream.ReadToEnd();
var xml = System.Xml.Linq.XElement.Parse(postresult);
if (xml.Elements("success").FirstOrDefault().Value == "1")
{
  lblgoodbad.Text = "It was good.";
}
else
{
  var errors = xml.Elements("errors");
  foreach (var error in errors.Elements("error"))
  {
    lblgoodbad.Text = error.Value;
  }
}

編輯＃2
感謝@Hussey的幫助 - 我只是對我的語法進行了一次快速調整，它正在運行。 我的完整語法如下所示：

    private void SendAsyncData()
{
  string connectionString = "Data Source=hmod;Initial Catalog=salesdb;uid=userid;password=password;MultipleActiveResultSets=True";
  DataTable grds = new DataTable();
  using (var con = new SqlConnection(connectionString))
  using (var cmd = new SqlCommand("procedureone", con))
  using (var da = new SqlDataAdapter(cmd))
  {
    cmd.CommandType = CommandType.StoredProcedure;
    da.Fill(grds);
  }
  var client = new HttpClient();
  var q = string.Empty;
  foreach (DataRow row in grds.Rows)
  {
    var parameterSet = new List<KeyValuePair<string, string>>();
    for (int i = 0; i < grds.Columns.Count; ++i)
    {
        parameterSet.Add(new KeyValuePair<string, string>(grds.Columns[i].ColumnName, row[i].ToString()));

    }

    var result = client.PostAsync("http://weneedsampledata/ashx", new FormUrlEncodedContent(parameterSet)).Result;
    string resultContent = result.Content.ReadAsStringAsync().Result;
    var xml = System.Xml.Linq.XElement.Parse(resultContent);
    if (xml.Elements("success").FirstOrDefault().Value == "1")
    {
      lblgoodbad.Text = "It was good.";
    }
    else
    {
      var errors = xml.Elements("errors");
      foreach (var error in errors.Elements("error"))
      {
        lblgoodbad.Text = error.Value;
      }
    }
  }
}

Answer 1

你可以加上這一行並嘗試：

在此之后：

string resultContent = await result.Content.ReadAsStringAsync();

添加這個：

XElement incomingXml = XElement.Parse(resultContent);

或者您也可以使用ReadAsStreamAsync嘗試此選項以將流讀入XmlDocument：

string resultContent = await result.Content.ReadAsStreamAsync();

XDocument incomingXml = XDocument.Load(resultContent);