[英]Export list of list to XML and vice-versa
我正在嘗試為我的Visual C#程序實現“打開/保存”功能。 我需要保存的對象是列表列表。 更具體地說,它是List<List<Components>>
,其中Components
是我的自定義類。 我設法導出它,並使用XML閱讀器讀取變量,但是當我將其重新導入程序時,我得到了錯誤的變量。 例如,導出之前的列表容量為2。導入之后,列表容量變為4。有什么幫助嗎?
如果您可以建議另一種“打開/保存”功能,請放心。 我只需要將自定義類列表的列表存儲並還原到文件中。
public void open_click(object send, EventArgs e)
{
XmlSerializer xml = new XmlSerializer(typeof(List<List<Components>>));
OpenFileDialog oDialog = new OpenFileDialog();
oDialog.Filter = "XML|*.xml";
if (oDialog.ShowDialog() == DialogResult.OK)
{
Variables.compBuffer = new List<List<Components>>();
using (FileStream s = File.OpenRead(oDialog.FileName))
using (StreamReader sw = new StreamReader(s))
{
Variables.compBuffer = (List<List<Components>>)xml.Deserialize(s);
}
}
}
//
public void saveAs_click(object send, EventArgs e)
{
XmlSerializer xml = new XmlSerializer(typeof(List<List<Components>>));
SaveFileDialog sDialog = new SaveFileDialog();
sDialog.FileName = "myLadder";
sDialog.Filter = "XML|*.xml";
sDialog.OverwritePrompt = true;
if (sDialog.ShowDialog() == DialogResult.OK)
{
using (FileStream s = File.OpenWrite(sDialog.FileName))
using (StreamWriter sw = new StreamWriter(s))
{
xml.Serialize(s, Variables.compBuffer);
}
}
}
//
public class Components
{
//Private variables
private string _type = "empty";
private string _name = "";
private int _time = 0; //If it's a "timer" (in ms)
private int _index = -1;
private string _comment = "";
private bool _output = false;
public Components() { }
public string Type
{
get { return this._type; }
set { this._type = value; }
}
public string Name
{
get { return this._name; }
set { this._name = value; }
}
public int Time
{
get { return this._time; }
set { this._time = value; }
}
public int Index
{
get { return this._index; }
set { this._index = value; }
}
public string Comment
{
get { return this._comment; }
set { this._comment = value; }
}
public bool Output
{
get { return this._output; }
set { this._output = value; }
}
public void reset()
{
_type = "empty";
_name = "";
_time = 0; //If it's a "timer" (in ms)
_index = -1;
_comment = "";
_output = false;
}
}
}
由於您沒有考慮xml特定的解決方案,因此我只將其作為二進制表示形式序列化到文件中,然后將其還原:
using System.IO;
[Serializable]
public class Components
{
...
}
var components = new List<Components>();
string pathToFile = @"c:\dev\components.bin";
SerializeFile(pathToFile, components);
var fetchComponents = DeserializeFile(pathToFile);
private void SerializeFile(string file, IList<Components> data)
{
using (Stream stream = File.Open(file, FileMode.Create))
{
var formatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
formatter.Serialize(stream, data);
}
}
private IList<Components> DeserializeFile(string file)
{
using (Stream stream = File.Open(file, FileMode.Create))
{
var formatter = new System.Runtime.Serialization.Formatters.Binary.BinaryFormatter();
return (List<Components>)formatter.Deserialize(stream);
}
}
該解決方案的缺點是您無法查看文件並瀏覽數據。 進一步的改進將是使用泛型,以便您可以序列化/反序列化任何類型的數據。
不要忘記使用[Serializable]
屬性標記要保存的班級
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