如何使用py2neo從作為python中的節點返回的recordList中提取信息？

Question

我的問題是，當我將結果作為recordList並且返回值是節點時，如何從recordList數據結構中提取信息，例如任何特定節點的屬性？

results = graph.cypher.execute("MATCH (n:Person) return n")
for index in range(len(results)):
        print results[index].n

回來：

(n3:Person {birthday:"17/8/2001",name:"John",sex:"male"})
(n4:Person {birthday:"17/8/2001",name:"John",sex:"male"})
(n5:Person {birthday:"17/8/2001",name:"John",sex:"male"})

如何從返回的recordList中提取名稱，性別屬性或唯一方法是編寫返回所有節點的名稱和性別的密碼？

Answer 1

節點具有.properties ：

results = graph.cypher.execute("MATCH (n:Person) RETURN n LIMIT 10")

for row in results:
    properties = row.n.properties
    print(properties['name'])