[英]Scala Seq[Type] Error when Pattern Matching
我有一個序列:
def myMethod(mySeq: Seq[SomeType]) = mySeq match {
case Nil => // do someting
case _ => // do something else (error happens here)
}
運行此代碼時,出現以下錯誤:
a type was inferred to be `Any`; this may indicate a programming error
到目前為止,我從未見過此錯誤。 我使用的是Scala 2.11。 我不知道這個錯誤是什么? 有什么線索嗎?
編輯:這是我所質疑的實際方法:
def publishMessages(mySeq: Seq[MyData]): Future[Continue] = Future {
if (mySeq.nonEmpty) {
logger.info(s"sending a total of ${mySeq.length} for " +
s"metric ${mySeq.head.metric} messages to kafka topic ${producerConfig.topic}")
val jsonMessage = Json.stringify(Json.toJson(mySeq))
val recordMetaDataF = Future {
scala.concurrent.blocking {
val recordMetaDataJavaFut = producer.send(
new ProducerRecord[String, String](producerConfig.topic, jsonMessage)
)
// if we don't make it to Kafka within 3 seconds, we timeout
recordMetaDataJavaFut.get(3, TimeUnit.SECONDS)
}
}
recordMetaDataF.recover {
case NonFatal(ex) =>
logger.error("Exception while persisting data-points to kafka", ex)
}
Continue
}
else {
logger.debug(s"skip persisting to kafka topic ${producerConfig.topic} as no " +
" data-points were given to persist")
Continue
}
}
這是編譯時看到的警告:
[warn] Scala version was updated by one of library dependencies:
[warn] * org.scala-lang:scala-library:(2.11.1, 2.11.7, 2.11.2, 2.11.6, 2.11.5, 2.11.0) -> 2.11.8
[warn] To force scalaVersion, add the following:
[warn] ivyScala := ivyScala.value map { _.copy(overrideScalaVersion = true) }
[warn] Run 'evicted' to see detailed eviction warnings
我仍然收到此錯誤:
a type was inferred to be `Any`; this may indicate a programming error
這與“執行某項操作”在您的應用中的含義有關:
scala> def myMethod(mySeq: Seq[String]) = mySeq match {
| case Nil => ""
| case _ => 12
| }
myMethod: (mySeq: Seq[String])Any
scala> def myMethod(mySeq: Seq[String]) = mySeq match {
| case Nil => ""
| case _ => "123"
| }
myMethod: (mySeq: Seq[String])String
如您所見,在第一種情況下,類型不對齊,並且編譯器推斷出的返回類型為Any
,在第二種情況下,它們都是字符串,返回的類型為String
,您應該顯式注釋返回類型,並且可能會不要編譯(除非它是Any
)。
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