I have a Seq as:
def myMethod(mySeq: Seq[SomeType]) = mySeq match {
case Nil => // do someting
case _ => // do something else (error happens here)
}
When I run this code, I get the following error:
a type was inferred to be `Any`; this may indicate a programming error
I have never seen this error thus far. I'm on Scala 2.11. I'm clueless as to what this error is? Any clues?
Edit: Here is the actual method that I have under question:
def publishMessages(mySeq: Seq[MyData]): Future[Continue] = Future {
if (mySeq.nonEmpty) {
logger.info(s"sending a total of ${mySeq.length} for " +
s"metric ${mySeq.head.metric} messages to kafka topic ${producerConfig.topic}")
val jsonMessage = Json.stringify(Json.toJson(mySeq))
val recordMetaDataF = Future {
scala.concurrent.blocking {
val recordMetaDataJavaFut = producer.send(
new ProducerRecord[String, String](producerConfig.topic, jsonMessage)
)
// if we don't make it to Kafka within 3 seconds, we timeout
recordMetaDataJavaFut.get(3, TimeUnit.SECONDS)
}
}
recordMetaDataF.recover {
case NonFatal(ex) =>
logger.error("Exception while persisting data-points to kafka", ex)
}
Continue
}
else {
logger.debug(s"skip persisting to kafka topic ${producerConfig.topic} as no " +
" data-points were given to persist")
Continue
}
}
Here is the warning that I see when I compile:
[warn] Scala version was updated by one of library dependencies:
[warn] * org.scala-lang:scala-library:(2.11.1, 2.11.7, 2.11.2, 2.11.6, 2.11.5, 2.11.0) -> 2.11.8
[warn] To force scalaVersion, add the following:
[warn] ivyScala := ivyScala.value map { _.copy(overrideScalaVersion = true) }
[warn] Run 'evicted' to see detailed eviction warnings
I still get this error:
a type was inferred to be `Any`; this may indicate a programming error
This has to do with what "do something" means in your app:
scala> def myMethod(mySeq: Seq[String]) = mySeq match {
| case Nil => ""
| case _ => 12
| }
myMethod: (mySeq: Seq[String])Any
scala> def myMethod(mySeq: Seq[String]) = mySeq match {
| case Nil => ""
| case _ => "123"
| }
myMethod: (mySeq: Seq[String])String
As you can see in the first case the type don't align and the return type inferred by the compiler is Any
, in the second they are both strings and the returned type is String
, you should explicitly annotate the return type and that probably won't compile (unless it's Any
).
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