如何在具有共同屬性的兩個節點之間創建關系？

Question

我想我正在問這個問題。 我的節點中的數據如下所示：

Car      Speed
---      -----
Farrari  80
Corvette 92
Farrari  135
Corvette 129
Porche   78
Porche   150

我想在兩輛相同的汽車之間建立一個名為HIGH_SPEED的關系，速度最快，車速最低。 所以基本上關系應該是這樣的：

                  ___________                        ___________
                 /           \                      /           \
                /             \    High Speed      /             \
               |  Car: Porche  |_________________\|  Car: Porche  |  
               |  Speed: 78    |                 /|  Speed: 150   |
                \             /                    \             /
                 \___________/                      \___________/

這是我到目前為止所得到的。 這會創建一個空關系。

MATCH (c_max:CARS), (c_min:CARS)
with c_max.name as max_name, max(c_max.speed) as max_speed
   , c_min.name as min_name, min(c_min.speed) as min_speed
WHERE c_max.name = c_min.name
FOREACH (x IN max_name |
  FOREACH (y IN min_name |
    CREATE (x)-[:HIGH_SPEED]->(y)))

Answer 1

如果您找到每種類型汽車的min和max ，然后直接匹配節點以獲得最高和最低速度並連接它們，那該怎么辦？

match (c:CARS)
with c.name as type, min(c.score) as min_speed, max(c.score) as max_speed
match (c1:CARS {name: type, score: min_speed}), (c2:CARS {name: type, score: max_speed})
create (c1)-[:HIGH_SPEED]->(c2)
return c1, c2