默認選擇angularjs中的所有復選框

Question

我正在 angularjs 中創建一個應用程序。 我在顯示頁面打開時選中的所有復選框時遇到問題。

這是我的代碼：

<div class="check_box">
<input type="checkbox" id="checkbox1" name="checkbox" ng-model="selectedAllStatus" ng-click="checkAllTypes()">
<label for="checkbox1"><span for="checkbox1">All</span></label>
</div>
</li>

<li ng-repeat="customersFlowsList in customersFlows | unique:'type'" ng-init="checkAllTypes()">

<div class="check_box">
<input type="checkbox" id="checkbox1" name="checkbox"  ng-model="filter[customersFlowsList.type]">
<label for="checkbox1"><span for="checkbox1">{{customersFlowsList.type | customerType}}</span></label>
</div>
</li>

這是我的js代碼：

$scope.checkAllStatus = function()
    {
       console.log($scope.selectedAll)
        if ($scope.selectedAll) {
            $scope.selectedAll = true;
        } else {
            $scope.selectedAll = false;
        }
        angular.forEach($scope.customersFlows, function (customersFlowsList) {
           $scope.filterLink[customersFlowsList.linkStatus] = $scope.selectedAll;
        });

    }

單擊按鈕時，所有復選框都被選中（這是有效的），但我希望當頁面打開時所有復選框都應該被選中。

Answer 1

您可以在模板加載之前在控制器中執行此操作

 $scope.checkAllStatus = function() {
   console.log($scope.selectedAll)
   if ($scope.selectedAll) {
     $scope.selectedAll = true;
   } else {
     $scope.selectedAll = false;
   }
   angular.forEach($scope.customersFlows, function(customersFlowsList)         {
     $scope.filterLink[customersFlowsList.linkStatus] = $scope.selectedAll;
   });

 }


  $scope.selectedAllStatus = true;
  $scope.checkAllStatus()