從FreeMarker模板訪問Java嵌套類

Question

public class MyModel {

  private final com.google.gson.Gson gson = new Gson();
  private final SomeData someData = new SomeData();

  private class SomeData extends JsonModel() {
    String text = "text";
  }

  private class JsonModel() {
    public String toJson() {
      return gson.toJson(this);
    }
  }

  public SomeData getSomeData() {
    return someData;
  }
}

假設MyModel是在訪問FTL作為myModel ，為什么myModel.someData.toJson或myModel.getSomeData().toJson()失敗， The following has evaluated to null or missing: myModel.someData.toJson或The following has evaluated to null or missing: myModel.getSomeData().toJson()嗎？

Answer 1

JsonModel必須是公共的，否則它的成員將不會暴露。