[英]How do I create a .sql file in ubuntu server?
我實際上有這個create.php代碼
<?php
//ENTER THE RELEVANT INFO BELOW
$mysqlUserName = "root";
$mysqlPassword = "admin";
$mysqlHostName = "localhost";
$DbName = "corporativostr_inventario";
$backup_name = "corporativostr_inventario.sql";
$tables = array("articulos","articulos_eliminados","categorias","conceptos","proveedores","registros","responsables","responsables_eliminados","usuarios","usuarios_eliminados");
//or add 5th parameter(array) of specific tables: array("mytable1","mytable2","mytable3") for multiple tables
Export_Database($mysqlHostName,$mysqlUserName,$mysqlPassword,$DbName, $tables=false, $backup_name=false );
function Export_Database($host,$user,$pass,$name, $tables=false, $backup_name=false )
{
$mysqli = new mysqli($host,$user,$pass,$name);
$mysqli->select_db($name);
$mysqli->query("SET NAMES 'utf8'");
$queryTables = $mysqli->query('SHOW TABLES');
while($row = $queryTables->fetch_row())
{
$target_tables[] = $row[0];
}
if($tables !== false)
{
$target_tables = array_intersect( $target_tables, $tables);
}
foreach($target_tables as $table)
{
$result = $mysqli->query('SELECT * FROM '.$table);
$fields_amount = $result->field_count;
$rows_num=$mysqli->affected_rows;
$res = $mysqli->query('SHOW CREATE TABLE '.$table);
$TableMLine = $res->fetch_row();
$content = (!isset($content) ? '' : $content) . "\n\n".$TableMLine[1].";\n\n";
for ($i = 0, $st_counter = 0; $i < $fields_amount; $i++, $st_counter=0)
{
while($row = $result->fetch_row())
{ //when started (and every after 100 command cycle):
if ($st_counter%100 == 0 || $st_counter == 0 )
{
$content .= "\nINSERT INTO ".$table." VALUES";
}
$content .= "\n(";
for($j=0; $j<$fields_amount; $j++)
{
$row[$j] = str_replace("\n","\\n", addslashes($row[$j]) );
if (isset($row[$j]))
{
$content .= '"'.$row[$j].'"' ;
}
else
{
$content .= '""';
}
if ($j<($fields_amount-1))
{
$content.= ',';
}
}
$content .=")";
//every after 100 command cycle [or at last line] ....p.s. but should be inserted 1 cycle eariler
if ( (($st_counter+1)%100==0 && $st_counter!=0) || $st_counter+1==$rows_num)
{
$content .= ";";
}
else
{
$content .= ",";
}
$st_counter=$st_counter+1;
}
} $content .="\n\n\n";
}
//$backup_name = $backup_name ? $backup_name : $name."___(".date('H-i-s')."_".date('d-m-Y').")__rand".rand(1,11111111).".sql";
$backup_name = $backup_name ? $backup_name : $name.".sql";
header('Content-Type: application/octet-stream');
header("Content-Transfer-Encoding: Binary");
header("Content-disposition: attachment; filename=\"".$backup_name."\"");
echo $content; exit;
}
?>
當我使用Web導航器在其他PC上打開.php文件時,它將創建一個可下載的.sql文件。
但是,當我在ubuntu服務器中運行它時,我只能看到數據庫內容。
如何在create.php所在的目錄中創建.sql文件?
您不能使用此代碼創建.sql文件,此代碼正在創建名稱為prueba
數據庫
為了創建.sql文件文件,我們使用命令行查詢(也可以在應用程序級別使用)。
mysqldump -u'user' -p'password' database_name > /path/filename.sql
這將創建一個.sql
文件,並且您可以在應用程序級別上使用相同的查詢來創建數據庫.sql,前提是該數據庫具有正確的使用權限。
如果數據庫具有子例程,則可以使用--routines等其他參數。 有許多可選參數。
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