檢查python系列是否在另一個列表中包含任何字符串

Question

我有一系列由24個字符組成的等長字符串，例如

my_series = ['ThisIsASentenceXXXXXXXXX', 'SoIsThisXXXXXXXXXXXXXXXX', 'YouGetThePointXXXXXXXXXX']

我也有一個列表，其中包含等長的4個字符的字符串，例如

my_list = ['This', 'XXXX', 'GetT']

我想將my_list中的每個條目與my_series中的每個條目中的4個字符的每個塊進行比較，並返回在其中找到列表字符串的my_series項目。

例如，對於my_list中的字符串'This'，我希望返回my_series項目1和2，而對於'XXXX'，則要返回my_series項目1,2,3。

Answer 1

下面的生成器將創建一個二維列表。 每個列表將包含任何匹配項，並且其位置將匹配my_list索引。

n_list = [[x for x in my_series if item in x] for item in my_list]

輸出：

[['ThisIsASentenceXXXXXXXXX'，'SoIsThisXXXXXXXXXXXXXXXX']，['ThisIsASentenceXXXXXXXXX'，'SoIsThisXXXXXXXXXXXXXXXX'，'YouGetThePointXXXXXXXXXX']，['YouGetThePointXXXXXXXXXX']]

因此n_list[0]包含my_list[0]等的匹配項...希望對您有所幫助！

Answer 2

您需要將my_series每個條目分成6個塊：

serires_chunks = [(s[0:4], s[4:8], s[8:12], s[12:16], s[16:20], s[20:24])
                  for s in my_series]

然后，您可以遍歷此塊以找到匹配的項目：

for item in my_list:
    for index, chunks in enumerate(serires_chunks):
        for place, chunk in enumerate(chunks, 1):
            if item == chunk:
                location = my_series[index]
                print("Found '{item}' in '{location}' at {place}".format(**locals()))

您將獲得：

Found 'This' in 'ThisIsASentenceXXXXXXXXX' at 1
Found 'This' in 'SoIsThisXXXXXXXXXXXXXXXX' at 2
Found 'XXXX' in 'ThisIsASentenceXXXXXXXXX' at 5
Found 'XXXX' in 'ThisIsASentenceXXXXXXXXX' at 6
Found 'XXXX' in 'SoIsThisXXXXXXXXXXXXXXXX' at 3
Found 'XXXX' in 'SoIsThisXXXXXXXXXXXXXXXX' at 4
Found 'XXXX' in 'SoIsThisXXXXXXXXXXXXXXXX' at 5
Found 'XXXX' in 'SoIsThisXXXXXXXXXXXXXXXX' at 6
Found 'XXXX' in 'YouGetThePointXXXXXXXXXX' at 5
Found 'XXXX' in 'YouGetThePointXXXXXXXXXX' at 6