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Facebook和Google登錄asp.net網站

[英]Facebook & Google Login for asp.net website

對於我的asp.net網站,我嘗試了FB和Google Login的功能。 我從ASPSNIPPETS找到了教程。 現在,我所做的就是如果用戶點擊Facebook登錄按鈕,那么它首先授權用戶並在面板中獲取用戶詳細信息。 然后我把我的代碼檢查用戶是否已經存在於我的數據庫中。 如果沒有,則插入用戶然后輸入登錄代碼。 我的問題是在執行第一行代碼后,它會停止執行,以便無法檢查用戶是否已登錄等等。 我認為這可能是因為重定向url會停止執行更多代碼。 我該如何消除這個問題?

Protected Sub Login(sender As Object, e As EventArgs)
        FaceBookConnect.Authorize("user_photos,email", Request.Url.AbsoluteUri.Split("?"c)(0))

If Not String.IsNullOrEmpty(lblId.Text) Then
            Dim query As String = "Select ID, email From users where ID=@id"
            con.Open()
            Dim cmd As New MySqlCommand(query, con)
            cmd.Parameters.AddWithValue("@id", lblId.Text)
            Dim dr As MySqlDataReader = cmd.ExecuteReader()
            If dr.HasRows Then
                'Do Login Code here
                Try
                    Dim str As String = "select * from users where ID='" + lblId.Text + "';"
                    Dim cmd2 As New MySqlCommand(str, con)
                    Dim da As New MySqlDataAdapter(cmd2)
                    Response.Cookies("User_Type").Value = "users"
                    Response.Cookies("chkusername").Value = lblId.Text
                    Response.Redirect(Request.Url.AbsoluteUri)
                    welcome.Visible = True
                Catch ex As Exception
                    Response.Write(ex)
                End Try
            Else
                Try
                    Dim str1 As String = "INSERT INTO users (ID, DP, displayName) values('" + lblId.Text + "', '" + ProfileImage.ImageUrl.ToString + "', '" + lblName.Text + "')"
                    Dim adapter As New MySqlDataAdapter
                    Dim command As New MySqlCommand
                    dr.Close()
                    command.CommandText = str1
                    command.Connection = con
                    adapter.SelectCommand = command
                    command.ExecuteNonQuery()
                Catch ex As Exception
                    Response.Write(ex)
                End Try


                Dim con2 As New MySqlConnection("connectionstring")
                con2.Open()
                Dim cmd3 As New MySqlCommand("Select ID, email From users where ID=@id", con2)
                cmd3.Parameters.AddWithValue("@id", lblId.Text)
                Dim dr2 As MySqlDataReader = cmd3.ExecuteReader()
                If dr2.HasRows Then
                    'Do Login Code here
                    Try
                        Dim str As String = "select * from users where ID='" + lblId.Text + "';"
                        Dim cmd2 As New MySqlCommand(str, con2)
                        con2.Open()
                        Dim da As New MySqlDataAdapter(cmd3)
                        Response.Cookies("User_Type").Value = "users"
                        Response.Cookies("chkusername").Value = lblId.Text
                        Response.Redirect(Request.Url.AbsoluteUri)
                    Catch ex As Exception
                        Response.Write(ex)
                        con2.Close()
                    End Try
                    con.Close()
                End If

            End If
        End If
        con.Close()
    End Sub

首先,您可以優化代碼:

        If Not String.IsNullOrEmpty(lblId.Text) Then
        Dim str As String = "select * from users where ID=@id"
        con.Open()
        Dim cmd2 As New MySqlCommand(str, con)
        cmd.Parameters.AddWithValue("@id", lblId.Text)
        Dim da As New Common.DataAdapter(cmd2)
        Dim ds As New Data.DataSet()
        da.Fill(ds)
        If ds.Tables(0).Rows.Count > 0 Then
            'Do Login Code here
            Try

                Response.Cookies("User_Type").Value = "users"
                Response.Cookies("chkusername").Value = lblId.Text
                Response.Redirect(Request.Url.AbsoluteUri)
                welcome.Visible = True
            Catch ex As Exception
                Response.Write(ex)
            End Try
        Else
            Try
                Dim str1 As String = "INSERT INTO users (ID, DP, displayName) values(@id, @img,@name)"
                Dim cmd As New MySqlCommand
                cmd = New SqlCommand(req, con)
                cmd.Parameters.Add(New SqlParameter("@id", lblId.Text))
                cmd.Parameters.Add(New SqlParameter("@img", ProfileImage.ImageUrl.ToString))
                cmd.Parameters.Add(New SqlParameter("@name", lblName.Text))
                cmd.ExecuteNonQuery()
            Catch ex As Exception
                Response.Write(ex)
            End Try
            'After insertion you don't have to select  from database just send the parameters to cookies
            Response.Cookies("User_Type").Value = "users"
            Response.Cookies("chkusername").Value = lblId.Text
            Response.Redirect(Request.Url.AbsoluteUri)

        End If
        con.Close()
    End If

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