僅當組中的所有記錄均符合條件時才分組並返回結果

Question

數據庫結構如下：

地址有很多計划計划有很多工作職位有很多UserJobs

我試圖將針對特定地址完成的所有工作歸為一組，而不管計划如何。

從那里，我只想看到尚未完成一項成功工作的地址

成功的工作是當UserJobs.perfomance =准時或UserJobs.perfomance =晚

SELECT
  "addresses"."address1",
  "user_jobs"."performance"

FROM
  "addresses" JOIN "plans" ON "addresses"."id" = "plans"."address_id" 
  JOIN "jobs" ON "plans"."id" = "jobs"."plan_id" 
  JOIN "user_jobs" ON "jobs"."id" = "user_jobs"."job_id"

group by   
  "addresses"."address1",
  "user_jobs"."performance"

我嘗試構建上面的查詢，但是我已經看到了它的缺陷。 它將按地址分組，但如果該地址內有不同的演奏，它將拆分

Answer 1

如果要統計已完成的工作，可以使用條件聚合 ：

SELECT
  "addresses"."address1",
  COUNT(CASE 
           WHEN "user_jobs"."performance" IN ('ontime', 'late') THEN 1
        END) AS cnt  
FROM
  "addresses" JOIN "plans" ON "addresses"."id" = "plans"."address_id" 
  JOIN "jobs" ON "plans"."id" = "jobs"."plan_id" 
  JOIN "user_jobs" ON "jobs"."id" = "user_jobs"."job_id"    
GROUP BY   
  "addresses"."address1

Answer 2

“組中的所有記錄均符合條件”-> bool_and聚合函數

select "addresses"."address1" FROM
    "addresses" JOIN "plans" ON "addresses"."id" = "plans"."address_id" 
    JOIN "jobs" ON "plans"."id" = "jobs"."plan_id" 
    JOIN "user_jobs" ON "jobs"."id" = "user_jobs"."job_id"

   group by   
     "addresses"."address1"
   HAVING bool_and("user_jobs"."performance" IN ('ontime', 'late'))