仅当组中的所有记录均符合条件时才分组并返回结果

Question

数据库结构如下：

地址有很多计划计划有很多工作职位有很多UserJobs

我试图将针对特定地址完成的所有工作归为一组，而不管计划如何。

从那里，我只想看到尚未完成一项成功工作的地址

成功的工作是当UserJobs.perfomance =准时或UserJobs.perfomance =晚

SELECT
  "addresses"."address1",
  "user_jobs"."performance"

FROM
  "addresses" JOIN "plans" ON "addresses"."id" = "plans"."address_id" 
  JOIN "jobs" ON "plans"."id" = "jobs"."plan_id" 
  JOIN "user_jobs" ON "jobs"."id" = "user_jobs"."job_id"

group by   
  "addresses"."address1",
  "user_jobs"."performance"

我尝试构建上面的查询，但是我已经看到了它的缺陷。 它将按地址分组，但如果该地址内有不同的演奏，它将拆分

Answer 1

如果要统计已完成的工作，可以使用条件聚合 ：

SELECT
  "addresses"."address1",
  COUNT(CASE 
           WHEN "user_jobs"."performance" IN ('ontime', 'late') THEN 1
        END) AS cnt  
FROM
  "addresses" JOIN "plans" ON "addresses"."id" = "plans"."address_id" 
  JOIN "jobs" ON "plans"."id" = "jobs"."plan_id" 
  JOIN "user_jobs" ON "jobs"."id" = "user_jobs"."job_id"    
GROUP BY   
  "addresses"."address1

Answer 2

“组中的所有记录均符合条件”-> bool_and聚合函数

select "addresses"."address1" FROM
    "addresses" JOIN "plans" ON "addresses"."id" = "plans"."address_id" 
    JOIN "jobs" ON "plans"."id" = "jobs"."plan_id" 
    JOIN "user_jobs" ON "jobs"."id" = "user_jobs"."job_id"

   group by   
     "addresses"."address1"
   HAVING bool_and("user_jobs"."performance" IN ('ontime', 'late'))