[英]How to serialize C# objects to generate specific JSON
我正在嘗試創建如下所示的JSON,以通過TCP傳遞給外部。
{“方法”:“抖動”,“參數”:[10,否,{“像素”:1.5,“時間”:8,“超時”:40}],“標識”:42}
我接近了,但這是我得到的:
{“方法”:“抖動”,“參數”:[10,否, “ {”像素”:1.5,“時間”:8,“超時”:40} “ ],“ id”:42}
注意params數組的第3個元素周圍的引號。
對於解決此問題,我將不勝感激。 這是我的代碼:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Json;
using System.IO;
using System.Collections;
using System.Xml;
using System.Reflection;
namespace DitherTest
{
[CollectionDataContract]
public class DitherParametersList : ArrayList
{
public DitherParametersList() : base()
{}
}
[DataContract]
public class Dither
{
[DataMember( Name="method", Order=1)]
public string Method { get; set; }
[DataMember( Name="params", Order=2)]
public DitherParametersList Parameters { get; set; }
[DataMember( Name="id", Order=3)]
public int Id { get; set; }
}
[DataContract( Namespace="")]
public class Settle
{
[DataMember( Name = "pixels" )]
public double Pixels { get; set; }
[DataMember( Name = "time" )]
public int Time { get; set; }
[DataMember( Name = "timeout" )]
public int Timeout { get; set; }
public string SerializeJson()
{
return this.ToJSON();
}
}
static class Extensions
{
public static string ToJSON<T>( this T obj ) where T : class
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer( typeof( T ) );
using ( MemoryStream stream = new MemoryStream() )
{
serializer.WriteObject( stream, obj );
return Encoding.Default.GetString( stream.ToArray() );
}
}
}
class Program
{
static void Main( string[] args )
{
double ditherAmount = 10.0;
bool ditherRaOnly = false;
Settle settle = new Settle { Pixels = 1.5, Time = 8, Timeout = 40 };
DitherParametersList parameterList = new DitherParametersList();
parameterList.Add( ditherAmount );
parameterList.Add( ditherRaOnly );
string settleStr = settle.SerializeJson();
parameterList.Add( settleStr );
Dither dither = new Dither { Method = "dither", Parameters = parameterList, Id=42 };
string temp = dither.ToJSON();
}
}
}
提前致謝
您告訴它使第三個arg成為字符串。 您將其序列化為字符串,然后將其作為arg插入。
你需要
parameterList.Add( settle );
首先,請確保使用newtonsoft.com/json,如他的評論中提到的pm100 。 我已經更改了您的代碼,使其可以與newtonsoft.json一起使用,並且完全滿足您的要求:
{"method": "dither", "params": [10, false, {"pixels": 1.5, "time": 8, "timeout": 40}], "id": 42}
我刪除了您創建的DitherParametersList並使用了這些模型:
public class Dither
{
[JsonProperty("method", Order = 1)]
public string Method { get; set; }
[JsonProperty("params", Order = 2)]
public ArrayList Parameters { get; set; }
[JsonProperty("id", Order = 3)]
public int Id { get; set; }
}
public class Settle
{
[JsonProperty("pixels")]
public double Pixels { get; set; }
[JsonProperty("time")]
public int Time { get; set; }
[JsonProperty("timeout")]
public int Timeout { get; set; }
}
並輕松序列化它們:
class Program
{
static void Main(string[] args)
{
var settle = new Settle { Pixels = 1.5, Time = 8, Timeout = 40 };
var parameterList = new ArrayList { 10, false, settle };
var dither = new Dither { Method = "dither", Parameters = parameterList, Id = 42 };
string temp = JsonConvert.SerializeObject(dither);
}
}
引號來自您在此處進行的第一個序列化:
string settleStr = settle.SerializeJson();
假設您要避免使用Newtonsoft庫,一個直接的解決方法是簡單地將它們修剪掉:
string settleStr = settle.SerializeJson().Trim('"');
一個更強大的解決方案將只需要序列化一次。 如果您使用List{string}
而不是DitherParamtersList
,則可以執行以下操作:
Settle settle = new Settle { Pixels = 1.5, Time = 8, Timeout = 40 };
var parameterList = new List<string>()
{
ditherAmount.ToString(),
ditherRaOnly.ToString(),
string.Join(",", settle.Pixels, settle.Time, settle.Timeout)
};
Dither dither = new Dither { Method = "dither", Parameters = parameterList, Id = 42 };
string temp = dither.ToJSON();
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