python pygame如何反跳按鈕？

Question

因此，我正在建立一個基於pi的機器人。 它使用ps3控制器進行輸入。 按下X按鈕時，它會拍照。 由於某種原因，一次拍攝約5張照片。 有沒有辦法反彈輸入，使其只能識別一次按動？

我假設每次都在注冊多台印刷機...部分代碼已附加，但我必須聲明大部分代碼都來自piborg.org

joystick = pygame.joystick.Joystick(0)

button_take_picture = 14            # X button

while running:
    # Get the latest events from the system
    hadEvent = False
    events = pygame.event.get()
    # Handle each event individually
    for event in events:
        if event.type == pygame.QUIT:
            # User exit
            running = False
        elif event.type == pygame.JOYBUTTONDOWN:
            # A button on the joystick just got pushed down
            hadEvent = True
        elif event.type == pygame.JOYAXISMOTION:
            # A joystick has been moved
            hadEvent = True
        if hadEvent:
            if joystick.get_button(button_take_picture):
                take_picture()

Answer 1

似乎正在發生的事是X按鈕停留了多個幀。 在此期間可能還會發生其他一些事件，從而導致在每個幀中調用代碼中的take_picture() 。 要解決此問題，您可以僅在JOYBUTTONUP （釋放按鈕時take_picture()上調用take_picture() ，或將if joystick.get_button(button_take_picture)部分移至pygame.JOYBUTTONDOWN部分內。

另外，您可以使用另一個變量來指示是否已拍攝照片，如下所示：

picture_was_taken = False

while running:
     hadEvent = False
     events = pygame.event.get()
     for event in events:
       ...
       if event.type == pygame.JOYBUTTONUP:
           if not joystick.get_button(button_take_picture)
               picture_was_taken = False
       ...
       if hadEvent:
           if joystick.get_button(button_take_picture) and not picture_was_taken:
               take_picture()
               picture_was_taken = True