[英]Deserializing XML into object returns null values
我正在嘗試反序列化 XML 文檔,但我使用的代碼每次都返回 Null 值。
我有一個這樣的 XML
<?xml version="1.0" encoding="utf-8"?>
<RegistrationOpenData xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://example.gov">
<Description>Registration data is collected by ABC XYZ</Description>
<InformationURL>http://www.example.com/html/hpd/property-reg-unit.shtml</InformationURL>
<SourceAgency>ABC Department of Housing</SourceAgency>
<SourceSystem>PREMISYS</SourceSystem>
<StartDate>2016-02-29T00:03:06.642772-05:00</StartDate>
<EndDate i:nil="true" />
<Registrations>
<Registration xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<RegistrationID>108260</RegistrationID>
<BuildingID>4731</BuildingID>
</Registration>
</Registrations>
</RegistrationOpenData>
為了反序列化它,我創建了一個類
using System.Xml.Serialization;
using System.Xml;
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(Namespace="http://example.gov")]
[System.Xml.Serialization.XmlRootAttribute(Namespace="http://example.gov", IsNullable=true)]
public partial class Registration : InfoClass {
private long registrationIDField;
private bool registrationIDFieldSpecified;
private System.Nullable<long> buildingIDField;
private bool buildingIDFieldSpecified;
public long RegistrationID
{
get
{
return this.registrationIDField;
}
set
{
this.registrationIDField = value;
}
}
[System.Xml.Serialization.XmlIgnoreAttribute()]
public bool RegistrationIDSpecified {
get {
return this.registrationIDFieldSpecified;
}
set {
this.registrationIDFieldSpecified = value;
}
}
[System.Xml.Serialization.XmlElementAttribute(IsNullable=true)]
public System.Nullable<long> BuildingID {
get {
return this.buildingIDField;
}
set {
this.buildingIDField = value;
}
}
[System.Xml.Serialization.XmlIgnoreAttribute()]
public bool BuildingIDSpecified {
get {
return this.buildingIDFieldSpecified;
}
set {
this.buildingIDFieldSpecified = value;
}
}
我使用的代碼是
public void Test()
{
Registration RegistrationVal = null;
var xRoot = new XmlRootAttribute();
xRoot.ElementName = "RegistrationOpenData";
xRoot.Namespace = "http://services.hpd.gov";
xRoot.IsNullable = true;
var serializer = new XmlSerializer(typeof(Registration), xRoot);
using (TextReader reader = new StreamReader(@"D:\sample.xml"))
{
RegistrationVal = (Registration)serializer.Deserialize(reader);
}
}
這里它總是返回 Null 值。 預先感謝您的幫助。
您的問題出在 xml 中,因為它有一個注冊列表。 如果您刪除<Registration>
和<Registrations>
標記,則它可以工作。 您是否需要Registration
和Registrations
因為在這種情況下您必須使用Lists
。
你可以像在這個例子中那樣做(將嵌套的 xml 反序列化為 C# 對象)
並創建一個自己的類Registrations
,其中包含Registration
元素List
。
使用此代碼它可以工作。 創建一個超類:
[XmlRoot("RegistrationOpenData")]
public class RegistrationOpenData
{
[XmlElement("Registrations")]
public Registrations Regs { get; set; }
}
和Registrations
:
[XmlRoot("Registrations")]
public class Registrations
{
[XmlElement("Registration")]
public List<Registration> Regs { get; set; }
}
並且Registration
應該和以前一樣。 主要功能應更改為:
static void Main(string[] args)
{
RegistrationOpenData RegistrationVal = null;
var xRoot = new XmlRootAttribute();
xRoot.ElementName = "RegistrationOpenData";
xRoot.Namespace = "http://services.hpd.gov";
xRoot.IsNullable = true;
var serializer = new XmlSerializer(typeof(RegistrationOpenData), xRoot);
using (TextReader reader = new StreamReader(@"D:\sample.xml"))
{
RegistrationVal = (RegistrationOpenData)serializer.Deserialize(reader);
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.