[英]How to pass arguments to Command Prompt in c# code?
使用下面的代碼,我只能啟動Visual Studio 2008命令提示符,但是現在,我必須將網站發布到本地驅動器上的目標路徑。
我需要執行以下命令的C#代碼:
msbuild / target:Build / p:BuildingProject = true; OutDir = C:\\ Temp \\ build \\ ccosapp.sln我的第一次嘗試(失敗-不執行任何操作):
下面是我嘗試的代碼,它什么都不做:
ProcessStartInfo oInfo = new ProcessStartInfo(@"C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat", @"msbuild C:\Users\Johan\Documents\Visual Studio 2008\Projects\PRJAPP\PRJAPP.sln");
oInfo.UseShellExecute = false;
oInfo.ErrorDialog = false;
oInfo.CreateNoWindow = true;
oInfo.RedirectStandardOutput = true;
System.Diagnostics.Process p = System.Diagnostics.Process.Start(oInfo);
System.IO.StreamReader oReader2 = p.StandardOutput;
string sRes = oReader2.ReadToEnd();
oReader2.Close();
另一嘗試(也失敗):
string strCmdText = "/k \"C:\\Program Files (x86)\\Microsoft Visual Studio 9.0\\VC\\vcvarsall.bat\" && msbuild /p:OutDir=C:\\Temp\\build \"C:\\Users\\Johan\\Documents\\Visual Studio 2008\\Projects\\CCOSApp\\ccosapp.sln\"";
System.Diagnostics.Process.Start("CMD.exe", strCmdText);
我在CMD窗口中收到錯誤:
無法將“ C:\\ Program”識別為內部或外部命令,可操作程序或批處理文件。
最后一次嘗試(也失敗-與我的第二次嘗試得到相同的錯誤):
/// <span class="code-SummaryComment"><summary></span>
/// Executes a shell command synchronously.
/// <span class="code-SummaryComment"></summary></span>
/// <span class="code-SummaryComment"><param name="command">string command</param></span>
/// <span class="code-SummaryComment"><returns>string, as output of the command.</returns></span>
public void ExecuteCommandSync(object command)
{
try
{
// create the ProcessStartInfo using "cmd" as the program to be run,
// and "/c " as the parameters.
// Incidentally, /c tells cmd that we want it to execute the command that follows,
// and then exit.
System.Diagnostics.ProcessStartInfo procStartInfo =
new System.Diagnostics.ProcessStartInfo("cmd", "/k " + command);
// The following commands are needed to redirect the standard output.
// This means that it will be redirected to the Process.StandardOutput StreamReader.
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
// Do not create the black window.
procStartInfo.CreateNoWindow = false;
// Now we create a process, assign its ProcessStartInfo and start it
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
// Get the output into a string
string result = proc.StandardOutput.ReadToEnd();
// Display the command output.
Console.WriteLine(result);
}
catch (Exception objException)
{
// Log the exception
}
}
/// <span class="code-SummaryComment"><summary></span>
/// Execute the command Asynchronously.
/// <span class="code-SummaryComment"></summary></span>
/// <span class="code-SummaryComment"><param name="command">string command.</param></span>
public void ExecuteCommandAsync(string command)
{
try
{
//Asynchronously start the Thread to process the Execute command request.
System.Threading.Thread objThread = new System.Threading.Thread(new ParameterizedThreadStart(ExecuteCommandSync));
//Make the thread as background thread.
objThread.IsBackground = true;
//Set the Priority of the thread.
objThread.Priority = ThreadPriority.AboveNormal;
//Start the thread.
objThread.Start(command);
}
catch (ThreadStartException objException)
{
// Log the exception
}
catch (ThreadAbortException objException)
{
// Log the exception
}
catch (Exception objException)
{
// Log the exception
}
}
string cmdStr = @" ""C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat""
cd ""C:\Users\Johan\Documents\Visual Studio 2008\Projects\CCOSApp""
msbuild /target:Build /p:BuildingProject=true;OutDir=C:\Temp\build
ccosapp.sln";
new VsFunctions().ExecuteCommandAsync(cmdStr);
我提供了這種解決方法:
StreamWriter w = new StreamWriter(@"C:\temp\publish.bat");
w.WriteLine(@"call ""C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat""");
w.WriteLine(@"call cd ""C:\Users\Johan\Documents\Visual Studio 2008\Projects\CCOSApp""");
w.WriteLine(@"call msbuild /target:Build /p:BuildingProject=true;OutDir=C:\Temp\build ccosapp.sln");
w.Close();
System.Diagnostics.Process proc = new System.Diagnostics.Process();
ProcessStartInfo psi = new ProcessStartInfo(@"publish.bat");
psi.WorkingDirectory = @"C:\temp\";
proc.StartInfo = psi;
proc.Start();
C:\\ Program'無法識別為內部或外部命令,可操作程序或批處理文件。
您收到此錯誤的原因是Program
和File
之間的路徑中有空間
嘗試在路徑的開頭和結尾加上雙引號
而不是傳遞可執行文件的整個路徑,而是嘗試通過以下方式將目錄更改為“ C:\\ Program Files(x86)\\ Microsoft Visual Studio 9.0 \\ VC \\”
oInfo.WorkingDirectory = @"C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\";
然后只需調用vcvarsass.bat
希望有幫助
使用StartInfo
的Arguments
屬性時是否StartInfo
Process cmd = new Process();
cmd.StartInfo.CreateNoWindow = false;
cmd.StartInfo.UseShellExecute = false;
cmd.StartInfo.FileName = @"C:\Program Files (x86)\Microsoft Visual Studio 9.0\VC\vcvarsall.bat";
cmd.StartInfo.Arguments = @"msbuild C:\Users\Johan\Documents\Visual Studio 2008\Projects\PRJAPP\PRJAPP.sln";
cmd.Start();
cmd.WaitForExit();
即像在此示例中一樣: 從C#使用cmd.exe
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