嘗試從 C# 啟動 python.exe 時出錯

Question

我正在嘗試從 C# 執行 python 腳本。 我在以下鏈接的另一篇文章中找到了一種方法來完成此操作： run a python script from c# 。 但是，當進程到達 using (Process process = Process.Start(start))行時，我收到錯誤消息。 這是我正在實施的代碼：

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;


namespace RunPy
{
    class Program
    {
        static void Main(string[] args)
        {
            // As an example, cmd would be @C:/Python26/python.exe and args would be C://Python26//test.py 100
            String cmd = "@C:/Program Files (x86)/Python27/python.exe";
            String argss = "C:/My_Python_lib/happyBirthday.py 'joe'";
            // Console.Write(argss); this line is just to test the output of the above argss
            // Console.ReadLine(); this line goes with the above line to prevent the window from closing so fast
            run_cmd(cmd, argss);
            //ProcessStartInfo startInfo = new ProcessStartInfo();
            //startInfo.FileName = cmd;
            //Process.Start(cmd);

        }
        private static void run_cmd(string cmd, string args)
        {
            ProcessStartInfo start = new ProcessStartInfo();
            start.FileName = cmd;
            start.Arguments = args;
            start.UseShellExecute = false;
            start.RedirectStandardOutput = true;
            using (Process process = Process.Start(start))
            {
                using (StreamReader reader = process.StandardOutput)
                {
                    string result = reader.ReadToEnd();
                    Console.Write(result);
                }
            }
        }
    }
}

這是我回來的錯誤：

System.dll 中發生類型為“System.ComponentModel.Win32Exception”的未處理異常

任何幫助將不勝感激。 謝謝！

Answer 1

您錯誤地初始化了cmd變量。 "@" 應該在引號之前（即@"C:/..."）。 當然，使用正斜杠而不是反斜杠無論如何都不需要逐字字符串，因此您可以完全省略“@”。

String cmd = "C:/Program Files (x86)/Python27/python.exe";

Answer 2

試試看

string cmd = @"C:\Program Files (x86)\Python27\python.exe";

或

string cmd = @"C:\PROGRA~1\Python27\python.exe";

Answer 3

首先讀取python exe並將其加載到內存中。

var assembly = Assembly.GetExecutingAssembly();
var resourcePath = assembly.GetManifestResourceNames().Single(str => str.EndsWith("python.exe"));
FileStream outputFileStream = new FileStream(Path.Combine(Directory.GetCurrentDirectory(), resourcePath), FileMode.OpenOrCreate, FileAccess.ReadWrite);
using (Stream stream = assembly.GetManifestResourceStream(resourcePath))
{
    if (stream != null)
    {
        stream.CopyTo(outputFileStream);
        stream.Close();
    }
    outputFileStream.Close();
}