Python中第二個定義的語法錯誤

Question

def specificChecker(someThing, checker):
    if checker == None:
        return someThing
    elif checker == True:
        return not someThing
    else:
        return None

def whatDoesTheCheckerSay(someThing):
    if specificChecker(someThing) == someThing:
        return 'The checker value was False on that one.'
    elif specificChecker(someThing) == not someThing:
        return 'The checker value was True on that one.'
    elif specificChecker(someThing) == None:
        return 'Something irregular happend. The checker value wasn\'t None or True.'
    else:
        return 'Something went really wrong. This doesn\'t even not work.'

reallySomeThing = input('Type in really some thing: ')
theChecker = input('Set the checker to something: ')

print(specificChecker(reallySomeThing, theChecker))
print(whatDoesTheCheckerSay(reallySomeThing)) # This can be made more efficient, right?

def one(someShit):
    return someShit + ' AWWW YEAH!'

def two(someShit):
    return one(someShit)

print(two(input('Type in some kind of stuff: ')))

我是一個自學成才的初學者，所以毫無疑問這是一個尷尬的基礎。 我正在使用IDLE Shell，並在代碼的第二個定義語句中反復遇到語法錯誤。 請幫忙？

Answer 1

您不能使用以下行：

elif specificChecker(someThing) == not someThing:

這必須寫

elif specificChecker(someThing) != someThing:

是有效的Python。

這也是有效的，但可讀性可能較低：

elif (specificChecker(someThing)) == (not someThing):

OP編輯后：

新的錯誤是參數（始終為1）與需要2個參數的函數不匹配。 您必須將兩個參數傳遞給specificChecker而不是一個

Answer 2

第12行： elif specificChecker(someThing) == not someThing:

如果要檢查某個變量是否不是某個變量， is not用於布爾值或用於值和字符串的!=