在Process.Start中接受多行字符串

Question

我正在從目錄位置解析路徑：

假設InitialPath = @"C:\\Users\\username\\Documents\\Visual Studio 2015\\Projects"

我有一個循環：

var list = new List<string>();

foreach(var folder in Directory.GetDirectories(InitialPath) {
    var folder = Path.GetFileName(folder);
    var file = Path.GetFileName(Directory.GetFiles(folder, "*.sln").Single());

    list.Add(InitialPath +  "\\" + folder + "\\" + file); //would then result something like "C:\Users\username\Documents\Visual Studio 2015\Projects\Folder1\Project1inFolder1.sln"
}

如果我嘗試從list路徑，並將其分配給richbox作為其.text值，它將返回單行文本。

但是當我在MessageBox上顯示它時，該字符串被分成兩行，如下所示：

我需要強迫它不要分成幾行。 我的意思是，無論字符串的長度如何，我都需要它是單行字符串，因為Process.Start()不會接受該字符串，因為它會被切成幾行。 請參閱以下參考：

PS: sorry for not being able to explain my question eligibly, english is not my natural language

以防萬一，這是我的代碼段：

using MaterialSkin;
using MaterialSkin.Controls;
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.IO;
using System.Linq;
using System.Security.Principal;

namespace The_Projects {
    public partial class MainForm : MaterialForm {
        public MainForm() {
            InitializeComponent();

            var materialSkinManager = MaterialSkinManager.Instance;
            materialSkinManager.AddFormToManage(this);
            materialSkinManager.Theme = MaterialSkinManager.Themes.LIGHT;
            materialSkinManager.ColorScheme = new ColorScheme(Primary.BlueGrey800, Primary.BlueGrey900, Primary.BlueGrey500, Accent.LightBlue200, TextShade.WHITE);
        }

        public class DirectoryInformation {
        private string _FolderName;
        private string _Solution;
        private DateTime _Created;
        private DateTime _Accessed;
        private DateTime _Modified;
        private string _SecIdentity;
        private string _NTAccount;
        private double _FileSize;
        private int _FileCount;

        public string FolderName {
            get { return _FolderName; }
            set { _FolderName = value; }
        }

        public string Solution {
            get { return _Solution; }
            set { _Solution = value; }
        }

        public DateTime Created {
            get { return _Created; }
            set { _Created = value; }
        }

        public DateTime Accessed {
            get { return _Accessed; }
            set { _Accessed = value; }
        }

        public DateTime Modified {
            get { return _Modified; }
            set { _Modified = value; }
        }

        public string SecIdentity {
            get { return _SecIdentity; }
            set { _SecIdentity = value; }
        }

        public string NTAccount {
            get { return _NTAccount; }
            set { _NTAccount = value; }
        }

        public double FileSize {
            get { return _FileSize; }
            set { _FileSize = value; }
        }

        public int FileCount {
            get { return _FileCount; }
            set { _FileCount = value; }
        }
    }

        public string InitialPath = @"X:\_\Document\Visual Studio 2015\Projects\";
        public string FolderPath = string.Empty;
        public string Solution = string.Empty;

        private void MainForm_Load(object sender, EventArgs e) {
            var projectList = new List<DirectoryInformation>();

            foreach(var dirs in Directory.GetDirectories(InitialPath)) {
                var ac = File.GetAccessControl(dirs);
                var di = new DirectoryInfo(dirs);

                var dirInf = new DirectoryInformation() {
                    FolderName = Path.GetFileName(dirs),
                    Solution = Path.GetFileName(Directory.GetFiles(dirs, "*.sln").Single()),
                    Created = Directory.GetCreationTime(dirs),
                    Accessed = Directory.GetLastAccessTime(dirs),
                    Modified = Directory.GetLastWriteTime(dirs),
                    SecIdentity = ac.GetOwner(typeof(SecurityIdentifier)).ToString(),
                    NTAccount = ac.GetOwner(typeof(SecurityIdentifier)).Translate(typeof(NTAccount)).ToString(),
                    FileSize = (double) di.EnumerateFiles("*.*", SearchOption.AllDirectories).Sum(x => x.Length) / 1024000,
                    FileCount = Directory.GetFiles(dirs, "*.*", SearchOption.AllDirectories).Count()
                };

                projectList.Add(dirInf);
            }

            lstProjectList.DataSource = projectList;
            lstProjectList.DisplayMember = "FolderName";
        }

        private void lstProjectList_SelectedIndexChanged(object sender, EventArgs e) {
            var project = lstProjectList.SelectedValue as DirectoryInformation;

            lblFolder.Text = project.FolderName;
            lblCreated.Text = project.Created.ToString();
            lblAccess.Text = project.Accessed.ToString();
            lblModified.Text = project.Modified.ToString();
            lblIdentifier.Text = project.SecIdentity;
            lblOwner.Text = project.NTAccount;
            lblSize.Text = project.FileSize.ToString("F2") + " MB";
            lblCount.Text = project.FileCount.ToString();

            FolderPath = InitialPath + project.FolderName;
            Solution = FolderPath + "\\" + project.Solution;
        }

        private void btnOpenProject_Click(object sender, EventArgs e) {
            Process.Start(@"C:\Program Files (x86)\Microsoft Visual Studio 14.0\Common7\IDE\devenv.exe", Solution);
            //Clipboard.SetText(Solution);
        }

        private void btnOpenFolder_Click(object sender, EventArgs e) {
            Process.Start("explorer.exe", FolderPath);
        }
    }
}

Answer 1

這就是您的MessageBox包裝文字的方式。 您在這里有兩個選擇：

• 創建一個自定義Forms類
• 創建一個僅用於顯示消息的表單對話框

編輯：

更改此：

 Process.Start(@"C:\Program Files (x86)\Microsoft Visual Studio 14.0\Common7\IDE\devenv.exe", Solution);

至

 Process.Start(@"C:\Program Files (x86)\Microsoft Visual Studio 14.0\Common7\IDE\devenv.exe", "\"" + Solution + "\"");

這里發生的是Process.Start方法的第二個參數被視為第一個參數給定的可執行文件的參數。 所以process.start所做的相當於打開命令提示符並鍵入以下內容（但不完全相同）：

 "C:\Program Files (x86)\Microsoft Visual Studio 14.0\Common7\IDE\devenv.exe" X:\_\Document\Visual Studio 2015\.....

並且命令提示符將（空格）視為參數分隔符，因此將X:\\_\\Document\\Visual視為一個參數，將Studio視為下一個，依此類推。 當在字符串周圍使用"\\""時，您將告訴Process.Start，整個內容（包括空格）是單個參數。

Answer 2

您的樣本中有一些錯誤，對我來說這有效，並且我獲得了所有* .sln文件

//this is just to show that you can get short file name if you need FileInfo
        var list = new Dictionary<string, string>();

        var files = Directory.GetFiles(InitialPath, "*.sln", SearchOption.AllDirectories);
        foreach (var file in files)
        {
            FileInfo fileInfo = new FileInfo(file);
            list.Add(fileInfo.Name, file);
        }

        Process.Start(list.FirstOrDefault().Value);

在我的電腦上開始沒有問題。 但是，如果您想讓devenv.exe以打開解決方案的方式開始，您可以這樣做

 Process.Start(@"C:\Program Files (x86)\Microsoft Visual Studio 14.0\Common7\IDE\devenv.exe", @"devenv/""" + fullFilePath + @"""");

您需要在參數devenv /中使用命令，並且必須將路徑括在雙引號（“ fullFilePath”）中。