[英]Extending ParentRunner in Junit
我想從ParentRunner
擴展測試。 我這樣做是為了學習,而不是任何特定的場景。 我有下面和下面的類,也有輸出。 我不明白一些事情:1。為什么“describeChild”被反復召喚3次? 2.為什么測試沒有運行?(“doOne”和“doTwo”)? 取消重新排列此行://結果result = JUnitCore.runClasses(arg0.getClass()); 正在執行測試,但我不明白為什么它會這樣工作? 3.最重要的是 - 那條線:@SuiteClasses({ChildOne.class,ChildTwo.class})? 它對代碼的行為沒有任何影響......非常感謝任何響應的人:-)
套房類:
@RunWith(FamilyRunner.class)
@SuiteClasses({ChildOne.class, ChildTwo.class, ChildThree.class})
public class Suite {
//nothing here
}
跑步者班:
public class FamilyRunner extends ParentRunner<ParentClass>{
public FamilyRunner(Class<?> klass) throws InitializationError {
super(klass);
}
@Rule
public TestName name = new TestName();
@Override
protected List<ParentClass> getChildren() {
List<ParentClass> list = new ArrayList<>();
System.out.println("Adding items to list");
list.add(new ChildOne());
list.add(new ChildTwo());
return list;
}
@Override
protected Description describeChild(ParentClass arg0) {
System.out.println("describeChild class: " + arg0.getClass().getSimpleName());
Description desc = Description.createTestDescription(name.getMethodName(),
name.getMethodName(), getClass().getAnnotations());
return desc;
}
@Override
protected void runChild(ParentClass arg0, RunNotifier arg1) {
System.out.println("runChild " + arg0.getClass().getSimpleName());
//Result result = JUnitCore.runClasses(arg0.getClass());
}
}
和:
public class ParentClass {
public ParentClass() {
System.out.println("created parent class");
}
}
public class ChildOne extends ParentClass {
public ChildOne() {
System.out.println("created ChildOne class");
}
@Test
public void doOne(){
System.out.println("doOne");
}
}
public class ChildTwo extends ParentClass {
public ChildTwo() {
System.out.println("created ChildTwo class");
}
@Test
public void doTwo(){
System.out.println("doTwo");
}
}
控制台打印:
Adding items to list
created parent class
created ChildOne class
created parent class
created ChildTwo class
describeChild class: ChildOne
describeChild class: ChildTwo
describeChild class: ChildOne
describeChild class: ChildTwo
describeChild class: ChildOne
describeChild class: ChildTwo
runChild ChildOne
runChild ChildTwo
我可以回答一些問題。
關於@SuiteClasses({ChildOne.class,ChildTwo.class})您沒有使用此注釋值構建列表。
你可以這樣做:
protected List<ParentClass> getChildren() {
Annotation[] runnerAnnotations = super.getRunnerAnnotations();
System.out.println(runnerAnnotations);
Optional<Annotation> suitClass = Arrays.stream(runnerAnnotations)
.filter(a -> a.annotationType().equals(SuiteClasses.class))
.findFirst();
List<ParentClass> list = new ArrayList<>();
if (suitClass.isPresent()) {
SuiteClasses s = (SuiteClasses) suitClass.get();
s.value();
System.out.println("Adding items to list");
for (Class<?> c : s.value()) {
Class<ParentClass> cp = (Class<ParentClass>) c;
try {
list.add(cp.newInstance());
} catch (InstantiationException | IllegalAccessException e) {
e.printStackTrace();
}
}
}
return list;
}
我想你可以在org.junit.runners.Suite來源找到更多信息: http : //grepcode.com/file/repo1.maven.org/maven2/junit/junit/4.8.1/org/junit/runners/Suite的.java
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