替換Python字典中的列表值

Question

我有以下字典。 對於值為['FAIL', 'PASS'] ，我只想將其替換為'PASS' 。

Dict = [('Main Menu-046', ['PASS']), ('Main Menu-047', ['FAIL']), ('Main Menu-044', ['FAIL', 'PASS']), ('Main Menu-045', ['PASS']), ('Main Menu-042', ['FAIL', 'PASS']), ('Main Menu-043', ['FAIL'])

我嘗試了以下方法：

if "FAIL" in [x for v in Dict.values() for x in v]: ## if true
    Dict.values == "PASS"

Answer 1

如果我正確理解了您的問題，則想將['FAIL', 'PASS']替換為['PASS']

processed_list = [(x[0], ["PASS"] if "PASS" in x[1] else x[1]) for x in Dict]

結果是：

[('Main Menu-046', ['PASS']),
 ('Main Menu-047', ['FAIL']),
 ('Main Menu-044', ['PASS']),
 ('Main Menu-045', ['PASS']),
 ('Main Menu-042', ['PASS']),
 ('Main Menu-043', ['FAIL'])]

Answer 2

您不使用字典，而是使用成對的列表(Main, [PASS/FAIL])

如果您想要一本字典，則可以通過d = { key:value, key:value ... }或d = dict()來創建它，並通過簡單地d['newkey'] = value添加項

另外，如果您願意，可以應用如下默認值：

from collections import defaultdict

d = defaultdict(lambda : defaultvalue)

當您有字典時，請嘗試如下循環：

for key in d.keys():
  if d[key] == 'FAIL': # or if 'FAIL' in d[key] if d[key] is a list like ['FAIL']
    d[key] = 'PASS' # or == ? why a boolean without condition or return ?