替换Python字典中的列表值

Question

我有以下字典。 对于值为['FAIL', 'PASS'] ，我只想将其替换为'PASS' 。

Dict = [('Main Menu-046', ['PASS']), ('Main Menu-047', ['FAIL']), ('Main Menu-044', ['FAIL', 'PASS']), ('Main Menu-045', ['PASS']), ('Main Menu-042', ['FAIL', 'PASS']), ('Main Menu-043', ['FAIL'])

我尝试了以下方法：

if "FAIL" in [x for v in Dict.values() for x in v]: ## if true
    Dict.values == "PASS"

Answer 1

如果我正确理解了您的问题，则想将['FAIL', 'PASS']替换为['PASS']

processed_list = [(x[0], ["PASS"] if "PASS" in x[1] else x[1]) for x in Dict]

结果是：

[('Main Menu-046', ['PASS']),
 ('Main Menu-047', ['FAIL']),
 ('Main Menu-044', ['PASS']),
 ('Main Menu-045', ['PASS']),
 ('Main Menu-042', ['PASS']),
 ('Main Menu-043', ['FAIL'])]

Answer 2

您不使用字典，而是使用成对的列表(Main, [PASS/FAIL])

如果您想要一本字典，则可以通过d = { key:value, key:value ... }或d = dict()来创建它，并通过简单地d['newkey'] = value添加项

另外，如果您愿意，可以应用如下默认值：

from collections import defaultdict

d = defaultdict(lambda : defaultvalue)

当您有字典时，请尝试如下循环：

for key in d.keys():
  if d[key] == 'FAIL': # or if 'FAIL' in d[key] if d[key] is a list like ['FAIL']
    d[key] = 'PASS' # or == ? why a boolean without condition or return ?