[英]Oracle LISTAGG case return distinct values
我正在用LISTAGG編寫ORACLE select語句。 它可以工作,但是當我驗證數據時,我看到了1:1,1:1,2:2,2:2之類的重復項。
我驗證數據庫確實有重復項。 查詢是一對一關系中的兩個表。 以下是我的查詢的摘要,但我更改了列名等。
如何修改以下查詢以返回每個人的唯一值?
謝謝
SELECT Table1.PERSON_ID,
Table1.FIRST_NAME,
Table1.MIDDLE_NAME,
Table1.LAST_NAME,
LISTAGG(case
when Table2.DESCRIPTION = '1' then '1:1'
when Table2.DESCRIPTION = '2' then '2:2'
when Table2.DESCRIPTION = '3' then '3:3'
when Table2.DESCRIPTION = '4' then '4:4'
when Table2.DESCRIPTION = '5' then '5:5'
when Table2.DESCRIPTION = '6' then '6:6'
when Table2.DESCRIPTION = '7' then '7:7'
when Table2.DESCRIPTION = '8' then '8:8'
when Table2.DESCRIPTION = '9' then '9:9'
else ''
end, ',')
WITHIN GROUP (ORDER BY Table2.DESCRIPTION )
FROM Table1
LEFT JOIN Table2
ON Table2.PERSON_ID = Table1.PERSON_ID
GROUP BY Table1.PERSON_ID,Table1.FIRST_NAME,Table1.MIDDLE_NAME, Table1.LAST_NAME
在Oracle中,您需要在子查詢中執行DISTINCT
:
SELECT PERSON_ID, FIRST_NAME, MIDDLE_NAME, LAST_NAME,
LISTAGG(val, ',') WITHIN GROUP (ORDER BY DESCRIPTION )
FROM (SELECT DISTINCT Table1.PERSON_ID, Table1.FIRST_NAME, Table1.MIDDLE_NAME, Table1.LAST_NAME, Table2.Description
(case when Table2.DESCRIPTION = '1' then '1:1'
when Table2.DESCRIPTION = '2' then '2:2'
when Table2.DESCRIPTION = '3' then '3:3'
when Table2.DESCRIPTION = '4' then '4:4'
when Table2.DESCRIPTION = '5' then '5:5'
when Table2.DESCRIPTION = '6' then '6:6'
when Table2.DESCRIPTION = '7' then '7:7'
when Table2.DESCRIPTION = '8' then '8:8'
when Table2.DESCRIPTION = '9' then '9:9'
else ''
end) as val
FROM Table1 LEFT JOIN
Table2
ON Table2.PERSON_ID = Table1.PERSON_ID
)
GROUP BY PERSON_ID, FIRST_NAME, MIDDLE_NAME, LAST_NAME;
假設Table2
將PERSON_ID
作為指向Table1
外鍵,則需要替換
FROM Table1
LEFT JOIN Table2
ON Table2.PERSON_ID = Table1.PERSON_ID
與
FROM Table1
LEFT JOIN
(SELECT DISTINCT PERSON_ID, DESCRIPTION FROM Table2) T2
ON T2.PERSON_ID = Table1.PERSON_ID
然后在LISTAGG()
中將Table2
更改為T2
(包括WITHIN GROUP (ORDER BY ...)
子句!)
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