[英]Oracle distinct listagg with count
我需要在每個表行中顯示一個逗號分隔的描述,但我需要使列表與眾不同,並且要對一些可用的描述進行計數。
every_description needs_count
---------------------------------
Bred yes
From Vendor yes
Grouped no
Removed yes
Separated no
Weaned yes
因此,一天之內的描述可能像Bred, Grouped, Weaned
,現在我可以使用LISTAGG
進行此工作,並使用此處提到的解決方案刪除重復項,但是我需要為5 Bred, Grouped, 2 Weaned
。
這是我目前遇到的問題:
WITH cages AS (
SELECT 1234 AS id FROM DUAL
UNION SELECT 5678 AS id FROM DUAL
UNION SELECT 9012 AS id FROM DUAL
UNION SELECT 3456 AS id FROM DUAL
), cage_comments AS (
SELECT 1234 AS cage_id, 'Bred' AS description, TO_DATE('11/14/2017', 'MM/DD/YYYY') AS event_date FROM DUAL
UNION SELECT 5678 AS cage_id, 'Grouped' AS description, TO_DATE('11/14/2017', 'MM/DD/YYYY') AS event_date FROM DUAL
UNION SELECT 9012 AS cage_id, 'Weaned' AS description, TO_DATE('11/14/2017', 'MM/DD/YYYY') AS event_date FROM DUAL
UNION SELECT 3456 AS cage_id, 'Weaned' AS description, TO_DATE('11/14/2017', 'MM/DD/YYYY') AS event_date FROM DUAL
UNION SELECT 3456 AS cage_id, 'Bred' AS description, TO_DATE('11/02/2017', 'MM/DD/YYYY') AS event_date FROM DUAL
UNION SELECT 3456 AS cage_id, 'Grouped' AS description, TO_DATE('11/14/2017', 'MM/DD/YYYY') AS event_date FROM DUAL
), calendar AS (
SELECT dt
FROM (
SELECT TRUNC(LAST_DAY(TO_DATE(&month || '/01/' || &year, 'MM/DD/YYYY')) - ROWNUM + 1) dt
FROM DUAL CONNECT BY ROWNUM <= 31
)
WHERE dt >= TRUNC(TO_DATE(&month || '/01/' || &year, 'MM/DD/YYYY'), 'MM')
ORDER BY dt ASC
)
SELECT
cal.dt,
(
SELECT
CASE
WHEN COUNT(cc.cage_id) > 0 THEN RTRIM(
REGEXP_REPLACE(
(LISTAGG(cc.description, ',') WITHIN GROUP (ORDER BY cc.description)),
'([^,]*)(,\1)+($|,)',
'\1\3'
),
','
)
ELSE NULL
END
FROM cages c
LEFT JOIN cage_comments cc ON cc.cage_id = c.id
WHERE cc.event_date = cal.dt
) AS description
FROM calendar cal
ORDER BY cal.dt
簡而言之-我很難為當天的某些說明添加COUNT
。 在上述情況下我想說的1 Bred
為November 2, 2017
和1 Bred, Grouped, 2 Weaned
為November 14, 2017
。
當前,您正在匯總所有描述(不使用DISTINCT),然后使用正則表達式replace刪除重復的描述。 這是非常低效的-選擇不重復然后應用LISTAGG會更好。
如果您需要添加計數,這將變得更加重要。 獲取您的加入和GROUP BY描述的結果。 (特別是,這將處理DISTINCT)。 在此聚合步驟的“選擇”中,包括計數。 然后將結果連接到問題頂部的其他表中,並將參數重寫為LISTAGG以包括CASE表達式,該表達式等於needs_count
值為'yes'
時的計數(和空格)。
您可以使用:
SELECT
cal.dt,
(
SELECT LISTAGG(CASE WHEN COUNT(*)=1 THEN ''
ELSE CAST(COUNT(*) AS VARCHAR2(10)) || ' ' END || description, ', ')
WITHIN GROUP (ORDER BY description)
FROM cages c
LEFT JOIN cage_comments cc ON cc.cage_id = c.id
WHERE cc.event_date = cal.dt
GROUP BY cc.event_date, cc.description
) AS description
FROM calendar cal
ORDER BY cal.dt;
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