[英]Accessing a nested XAML control within C#
我正在創建一個應用程序,其中WPF中的ListBox內的DataTemplate內有一個TextBox元素。 我想按名稱訪問TextBox元素以進行編輯,或直接從C#代碼中讀取值,請幫忙。 WPF應用程序中添加了多個TextBoxes,那么如何按索引對它們進行排序呢?
<ListBox x:Name="listBox" HorizontalAlignment="Left" Height="336" Margin="276,69,0,0" VerticalAlignment="Top" Width="242" SelectionChanged="listBox_SelectionChanged">
Grid.IsSharedSizeScope="True"
HorizontalContentAlignment="Stretch">
<ListBox.ItemTemplate>
<DataTemplate x:Name="D_Template">
<Grid Margin="4" Width="222">
<Grid.ColumnDefinitions>
<ColumnDefinition Width="Auto" SharedSizeGroup="Key" />
<ColumnDefinition Width="*" />
</Grid.ColumnDefinitions>
<TextBox x:Name ="TextValue" Grid.Column="1" Text="{Binding Value}" />
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
如您所見,ListBox具有變量名稱“ listBox”,DataTemplate已分配給“ D_Template”,而TextBox被分配給了名稱“ TextValue”。 感謝您的幫助,感謝您的寶貴時間。 :)
您應該真正將列表框項目源綁定到對象集合並讀取/更改它,而不是直接訪問文本框。但是如果由於某種原因您不願意或不想這樣做,此代碼可以為您提供幫助。 (請注意,我真的不鼓勵這種解決方案)
private void Button_Click(object sender, RoutedEventArgs e)
{ //pretend you want to access the second item
object myItem = myListbox.Items[1];
ListBoxItem container = myListbox.ItemContainerGenerator.ContainerFromItem(myItem) as ListBoxItem;
ContentPresenter contentPresenter = FindVisualChild<ContentPresenter>(container);
DataTemplate myDataTemplate = contentPresenter.ContentTemplate;
TextBox myTextbox = myDataTemplate.FindName("myTextbox", contentPresenter)as TextBox;
if (myTextbox != null)
{
myTextbox.Text = "text changed!";
}
}
public static IEnumerable<T> FindVisualChildren<T>(DependencyObject depObj) where T : DependencyObject
{
if (depObj != null)
{
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
{
DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
if (child != null && child is T)
{
yield return (T)child;
}
foreach (T childOfChild in FindVisualChildren<T>(child))
{
yield return childOfChild;
}
}
}
}
public static childItem FindVisualChild<childItem>(DependencyObject obj)
where childItem : DependencyObject
{
foreach (childItem child in FindVisualChildren<childItem>(obj))
{
return child;
}
return null;
}
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