如何使用JavaScript排序對樹JSON對象進行雙重排序？

Question

我需要param1排序z對象，然后按param2排序。 我的嘗試返回重復的對象實例，其中對象參數為整數且非唯一。

我該如何解決這個問題？

z=[{object1},{object2},{object3},...,{objectN}];
z.sort(function(x,y){
    if(x.param1-y.param1>0){return -1};
    if(x.param1-y.param1<0){return 1};
    if(x.param1-y.param1==0){
        if(x.param2-y.param2>0){return -1};
        if(x.param2-y.param2<0){return 1};
    }; 

});

z類似於：

z=[{"level":0,"order":0,"t":"section","a":{"class":"ro s-14 m-3"}},
    {"level":1,"order":0,"t":"h1","a":{"class":"tx-1 s-35"},"x":"This is a text"},
    {"level":1,"order":1,"t":"div","a":{"class":"tx-0 m-3"}},
        {"level":2,"order":0,"t":"h2","a":{"class":"tx-0 s-18"},"x":"This is a text"},
        {"level":2,"order":1,"t":"h3","a":{"class":"tx-0 s-14 fw-3"}},
            {"level":3,"order":0,"t":"li","x":"This is a text"},
            {"level":3,"order":1,"t":"li","x":"This is a text"},
            {"level":3,"order":2,"t":"li","x":"This is a text"},
            {"level":3,"order":3,"t":"li","x":"This is a text"},
            {"level":3,"order":4,"t":"li","x":"This is a text"},
            {"level":3,"order":5,"t":"li","x":"This is a text"},
            {"level":3,"order":6,"t":"li","x":"This is a text"},
            {"level":3,"order":7,"t":"li","x":"This is a text"},
            {"level":3,"order":8,"t":"li","x":"This is a text"},
        {"level":2,"order":2,"t":"h4","x":"This is a text"},
    {"level":1,"order":2,"t":"div","a":{"class":"tx-0 m-3"}},
        {"level":2,"order":0,"t":"h2","x":"This is a text"},
        {"level":2,"order":1,"t":"h3","a":{"class":"tx-0 s-12 fw-3"}},
            {"level":3,"order":0,"t":"li","x":"This is a text"},
            {"level":3,"order":1,"t":"li","x":"This is a text"},
            {"level":3,"order":2,"t":"li","x":"This is a text"},
            {"level":3,"order":3,"t":"li","x":"This is a text"},
            {"level":3,"order":4,"t":"li","x":"This is a text"},
            {"level":3,"order":5,"t":"li","x":"This is a text"},
            {"level":3,"order":6,"t":"li","x":"This is a text"},
            {"level":3,"order":7,"t":"li","x":"This is a text"},
            {"level":3,"order":8,"t":"li","x":"This is a text"},
            {"level":3,"order":9,"t":"li","x":"This is a text"},
            {"level":3,"order":10,"t":"li","x":"This is a text"},
            {"level":3,"order":11,"t":"li","x":"This is a text"},
        {"level":2,"order":2,"t":"h4","x":"This is a text"},
];

Answer 1

您的實現問題是對於param1和param2 ，如果返回值不正確，則您執行相同的操作。 您的更正將是：

z = [ { object1 }, { object2 }, { object3 },...,{ objectN }];
z.sort(function(x,y){
    if(x.param1-y.param1>0){return -1};
    if(x.param1-y.param1<0){return 1};
    if(x.param1-y.param1==0){
        if(x.param2-y.param2>0){return -1};
        if(x.param2-y.param2<0){return 1};
    }; 

});

順便說一句，我比您更喜歡這個：

 var items = [{ p1: 10, p2: 3 }, { p1: 9, p2: 4 }, { p1: 9, p2: 3 }, { p1: 10, p2: 2 }, { p1: 11, p2: 3 }, ]; items.sort((a, b) => (a.p1 - b.p1) || (a.p2 - b.p2)); console.log(items); 

如您所見，值的差異對排序函數很有意義，該函數允許您傳遞減法結果以用於排序。 如果difference為0（也意味着是false），那么它將用於第二個參數並返回其減法結果。

Answer 2

您可以對升序使用更緊湊的回調：

z.sort(function (x, y) {
    return x.param1 - y.param1 || x.param2 - y.param2;
});

或降序：

z.sort(function (x, y) {
    return y.param1 - x.param1 || y.param2 - x.param2;
});