如何在UI選擇值中選擇值？

Question

您能告訴我如何在UI選擇值中選擇值嗎？

實際上，當用戶選擇任何名稱時，我想選擇商品的年齡 。這是我的代碼http://plnkr.co/edit/InxOyQRjrlrDJtx2VuzI?p=preview

<ui-select tagging tagging-label="new tag" multiple ng-model="multipleDemo" theme="select2" ng-disabled="disabled" style="width: 300px;">
    <ui-select-match placeholder="Select colors...">{{$item.name}}</ui-select-match>
    <ui-select-choices repeat="color in people | filter:$select.search">
      {{color.name}}
    </ui-select-choices>
  </ui-select>

例

當我選擇Amalie MultipleDemo模型值是12或如果我選擇Wladimir是模型值“ 30” ..它是多重選擇的，因此模型應該是數組..

我們能做到嗎？

Answer 1

ui-select設計方法，它需要ng-model值作為object 。 在這里你給了一個原始類型

碼

$scope.model = {multipleDemo :[]};

HTML

<ui-select tagging tagging-label="new tag" multiple ng-model="model.multipleDemo" theme="select2" ng-disabled="disabled" style="width: 300px;">
    <ui-select-match placeholder="Select colors...">{{$item.name}}</ui-select-match>
    <ui-select-choices repeat="color.age as color in people | filter:$select.search">
      {{color.name}}
    </ui-select-choices>
</ui-select>
<p>Selected: {{test.multipleDemo}}</p>

Plunkr

Answer 2

UI更改只需在ui-select上添加on-select="OnClickSelect($item)"和on-remove="OnRemoveSelect($item)"

      <ui-select tagging tagging-label="new tag" multiple ng-model="multipleDemo" 
          on-select="OnClickSelect($item)" on-remove="OnRemoveSelect($item)"
          theme="select2" ng-disabled="disabled" style="width: 300px;">
        <ui-select-match placeholder="Select colors...">{{$item.name}}</ui-select-match>
        <ui-select-choices  repeat="color in people | filter:$select.search">
          {{color.name}}
        </ui-select-choices>
      </ui-select>
      <p>Selected: {{multipleDemo}}</p>

角度更改在controller內部添加這些功能

  $scope.OnClickSelect=function(item)   {
    $scope.multipleDemo.push(item.age)
  }

 $scope.OnRemoveSelect = function(item) { 
   var index = $scope.multipleDemo.indexOf(item.age);
   $scope.multipleDemo.splice(index, 1);     
 }

plnkr