[英]Search all properties that are string
無論如何,是否有必要更改“位置”,它將自動檢查所有包含字符串的屬性,而不是手動添加每個屬性名稱?
items.Where(m => m.Property1.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
|| m.Property2.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
|| m.Property3.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
|| m.Property4?.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
|| m.Property5?.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
|| m.Property6.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
|| m.Property7?.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0
));
謝謝。
我會用反射寫代碼...
public bool MyContains(object instance, string word)
{
return instance.GetType()
.GetProperties()
.Where(x => x.PropertyType == typeof(string))
.Select(x => (string)x.GetValue(instance, null))
.Where(x => x != null)
.Any(x => x.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0);
}
然后您的代碼將是
items.Where(m=>MyContains(m,word));
根據磅的答案:我接受了他的答案
我將其分解為兩個函數,因為無需獲取where中每個實例的字符串屬性。
public static class ObjectUtils
{
public static IEnumerable<PropertyInfo> GetPropertiesByType<TEntity>(TEntity entity, Type type)
{
return entity.GetType().GetProperties().Where(p => p.PropertyType == type);
}
public static bool CheckAllStringProperties<TEntity>(TEntity instance, IEnumerable<PropertyInfo> stringProperties, string word)
{
return stringProperties.Select(x => (string)x.GetValue(instance, null))
.Where(x => x != null)
.Any(x => x.IndexOf(word, StringComparison.CurrentCultureIgnoreCase) >= 0);
}
}
然后
var stringProperties = ObjectUtils.GetPropertiesByType(new Item(), typeof(string));
items.Where(x => ObjectUtils.CheckAllStringProperties(x, stringProperties, word)));
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