關閉對話框后再次打開對話框時，應用程序崩潰並給出“ java.lang.IllegalStateException”

Question

我有一個對話框，其中應在EditText填寫一些詳細信息。 如果在編輯文本為空時單擊肯定按鈕，則會顯示帶有消息的Snackbar ，並且對話框將關閉。 但是，當我再次打開對話框時，該應用程序會發出以下消息： java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first錯誤java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first 。

這是我擴大視圖的方式：

LayoutInflater inflater = this.getLayoutInflater();
addVenueDialog = inflater.inflate(R.layout.add_venue_dialog, null);

這是打開對話框並檢查編輯文本是否為空的背后的Java代碼：

case R.id.nav_add_venue:
            if (dialog == null) {

                LayoutInflater inflater = this.getLayoutInflater();
                View addVenueDialog = inflater.inflate(R.layout.add_venue_dialog, null);

                vName = (EditText) addVenueDialog.findViewById(R.id.vName);
                vAddress = (EditText) addVenueDialog.findViewById(R.id.vAddress);

                AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
                builder.setTitle("Title");
                builder.setView(addVenueDialog);
                builder.setPositiveButton("Add", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface dialogInterface, int i) {
                        if (isNetworkAvailable()) {
                            if (vName.getText().toString().isEmpty()) {
                                Snackbar snackbar = Snackbar
                                        .make(coordinatorLayout, "V name cannot be empty", Snackbar.LENGTH_SHORT);
                                snackbar.show();
                            } else if (vAddress.getText().toString().isEmpty()) {
                                Snackbar snackbar = Snackbar
                                        .make(coordinatorLayout, "V address cannot be empty", Snackbar.LENGTH_SHORT);
                                snackbar.show();
                            } else {
                                mDatabase.child("vs").child(user.getUid()).child("V name").setValue(vName.getText().toString());
                                mDatabase.child("vs").child(user.getUid()).child("V address").setValue(vAddress.getText().toString());
                            }
                        } else {
                            Snackbar snackbar = Snackbar
                                    .make(coordinatorLayout, "No internet connection", Snackbar.LENGTH_SHORT);
                            snackbar.show();
                        }
                    }
                });
                dialog = builder.create();
            }
            dialog.show();
            break;

我不知道為什么在關閉對話框后再次打開對話框時該應用程序崩潰。

請告訴我。

Answer 1

一個簡單的解決方案是保留AlertDialog的全局實例並重新使用它：

//global
private AlertDialog dialog;

現在在切換情況下：

case R.id.nav_add_venue:
    if(dialog == null) {
        LayoutInflater inflater = this.getLayoutInflater(); 
        View addVenueDialog = inflater.inflate(R.layout.add_venue_dialog, null); 

        builder.setView(addVenueDialog); 

        final EditText vName = (EditText) addVenueDialog.findViewById(R.id.vName); 
        final EditText vAddress = (EditText) addVenueDialog.findViewById(R.id.vAddress); 

        // Other code //
        dialog = builder.create();
     }
     dialog.show();
     break;

請記住dismiss對話框onDestroy方法，以避免內存泄漏：

public void onDestroy() {
   super.onDestroy();
   if(dialog != null) {
     dialog.dismiss();
   }
 }