在switch語句中為LINQ創建where條件

Question

因此，基本上，我必須獲得4個不同角色的4個不同的員工列表。 List of Roles是一個List of Enum如下所示：

public enum Roles {
       [Description("Level 1")]
       L1,

       [Description("Level 2")]
       L2,

       [Description("Level 3")]
       L3,

       [Description("Level 4")]
       L4
};

• L1可以查看L1 ， L2 ， L3和L4
• L2可以查看L2 ， L3和L4
• L3可以查看L3和L4 。
• L4沒有查看任何員工的權限。

現在下面是我如何編寫查詢以獲取員工的信息。

if (!Equals(Role, Enum.GetName(typeof(GlobalMethods.Roles), 3)))
{
      var _role = (GlobalMethods.Roles)Enum.Parse(typeof(GlobalMethods.Roles), Role,true);
      List<EmployeeViewModel> employees = new List<EmployeeViewModel>();
      switch (_role)
      {
            case GlobalMethods.Roles.L1:
                 employees = context.tblEmployees.Where(x => x.EmpID != homeViewModel.UserViewModel.EmpID).ToList().Select(x => new EmployeeViewModel
                 {
                      EmpActive = x.EmpActive,
                      EmpDOB = x.EmpDOB,
                      EmpName = x.EmpName
                 }).ToList();
                 break;
            case GlobalMethods.Roles.L2:
                 employees= context.tblEmployees.Where(x => x.EmpID != homeViewModel.UserViewModel.EmpID).ToList().Where(x=>x.EmpRole != Enum.GetName(typeof(GlobalMethods.Roles), 0)).Select(x => new EmployeeViewModel
                 {
                      EmpActive = x.EmpActive,
                      EmpDOB = x.EmpDOB,
                      EmpName = x.EmpName,
                 }).ToList();
                 break;
            case GlobalMethods.Roles.L3:
                 employees = context.tblEmployees.Where(x => x.EmpID != homeViewModel.UserViewModel.EmpID).ToList().Where(x.EmpRole != Enum.GetName(typeof(GlobalMethods.Roles), 0) && x.EmpRole != Enum.GetName(typeof(GlobalMethods.Roles), 1)).Select(x => new EmployeeViewModel
                 {
                      EmpActive = x.EmpActive,
                      EmpDOB = x.EmpDOB,
                      EmpName = x.EmpName,
                 }).ToList();
                 break;
            default: break;
      }
}

因此，在上面的代碼中，我具有相同的LINQ查詢，但是只有where條件不同。 有什么方法可以准備動態where條件並一次獲取列表？

Answer 1

這應該工作。 它假設每個GlobalMethods.Roles可以查看具有更大int值的所有角色。 您所指定的角色就是這種情況。

if (!Equals(Role, Enum.GetName(typeof(GlobalMethods.Roles), 3)))
{
     var _role = (GlobalMethods.Roles)Enum.Parse(typeof(GlobalMethods.Roles), Role, true);
     List<EmployeeViewModel> employees = new List<EmployeeViewModel>();
     string[] viewableRoles = GetViewableRoles(_role);
     employees = context.tblEmployees
                .Where(x => x.EmpID != homeViewModel.UserViewModel.EmpID && viewableRoles.Contains(x.EmpRole))
                .Select(x => new EmployeeViewModel
                {
                    EmpActive = x.EmpActive,
                    EmpDOB = x.EmpDOB,
                    EmpName = x.EmpName
                }).ToList();
}

private string[] GetViewableRoles(GlobalMethods.Roles userRole)
{
    //Uncomment if L4 can actually view no roles, including itself.
    // /if (userRole == GlobalMethods.Roles.L4)
    // {
    //  return new string[0];
    // }

    IEnumerable<GlobalMethods.Roles> allRoles = Enum.GetValues(typeof(GlobalMethods.Roles)).Cast<GlobalMethods.Roles>();
    return (from role in allRoles 
                where (int)role >= (int)userRole 
                select role.ToString()).ToArray();
}

Answer 2

這是簡化的，但是您可以執行以下操作：

class Program
{
    static void Main(string[] args)
    {
        var list = new List<Person>
        {
            new Person{ Name = "John" },
            new Person{ Name = "Amy" }
        };

        Func<Person, bool> pred = null;
        Roles role = Roles.RoleA;
        switch (role)
        {
            case Roles.RoleA:
                pred = p => p.Name.StartsWith("J");
                break;
            case Roles.RoleB:
                pred = p => p.Name.StartsWith("A") && p.Name.Length >= 3;
                break;
            default:
                break;
        }

        var result = list.Where(pred);
    }
}

class Person
{
    public string Name { get; set; }
}

enum Roles
{
    RoleA,
    RoleB
}

Answer 3

以下是通用的表達式樹擴展方法，可以滿足以下要求（您當然需要進行修改以適合您的特定要求）

• T是IEnumerable的最終類型

• T1是where子句中用於過濾的列的類型

• 在將Expression Tree to Func編譯Expression Tree to Func同時，聲明給定Type T外部擴展方法的ParameterExpression以便重用，盡管這也可以在Extension method和Func生成期間分別完成

  ParameterExpression parameterType = Expression.Parameter(typeof(T), "object");

   public static class CustomExpression { // Create Initial Expression Tree public static BinaryExpression InitialExpression<T,T1>( ParameterExpression parameterType string columnName, T1 value) { // Optional can be taken outside the Extension method to create a Func<T,bool> //ParameterExpression parameterType = Expression.Parameter(typeof(T), "object"); MemberExpression typeColumn = Expression.Property(parameterType, columnName); ConstantExpression constant = Expression.Constant(value, typeof(T1)); return Expression.NotEqual(typeColumn, constant); } // Create Combined Expression Tree public static BinaryExpression CombinedExpression<T,T1>(this BinaryExpression mainExpression, ParameterExpression parameterType string columnName, T1 value) { // Optional can be taken outside the Extension method to create a Func<T,bool> //ParameterExpression parameterType = Expression.Parameter(typeof(T), "object"); MemberExpression typeColumn = Expression.Property(parameterType, columnName); ConstantExpression constant = Expression.Constant(value, typeof(T1)); return Expression.And(mainExpression,Expression.NotEqual(typeColumn, constant)); } } 

以下是您的情況下的呼叫層次結構：

• 為Linq查詢聲明最終的二進制表達式：

  BinaryExpression finalBinaryExpression = null;

    switch (_role) { case GlobalMethods.Roles.L1: finalBinaryExpression = CustomExpression.InitialExpression<EmployeeViewModel,int> (parameterType,"EmpID",homeViewModel.UserViewModel.EmpID); break; case GlobalMethods.Roles.L2: finalBinaryExpression = CustomExpression.InitialExpression<EmployeeViewModel,int> (parameterType,"EmpID",homeViewModel.UserViewModel.EmpID) .CombinedExpression<EmployeeViewModel,Roles> (parameterType,"EmpRole",Enum.GetName(typeof(GlobalMethods.Roles), 0)); break; case GlobalMethods.Roles.L3: finalBinaryExpression = CustomExpression.InitialExpression<EmployeeViewModel,int> (parameterType,"EmpID",homeViewModel.UserViewModel.EmpID) .CombinedExpression<EmployeeViewModel,Roles> (parameterType,"EmpRole",Enum.GetName(typeof(GlobalMethods.Roles), 0)) .CombinedExpression<EmployeeViewModel,Roles> (parameterType,"EmpRole",Enum.GetName(typeof(GlobalMethods.Roles), 1)); break; } 

• 通過如下編譯二進制表達式來創建一個genericFunc

   Func<T, bool> filterFunc = Expression.Lambda<Func<T, bool>> (finalBinaryExpression, parameterType).Compile(); 

• 最終結果應用上面創建的Func

    var finalResult = context.tblEmployees.Where(o => filterFunc(o));