[英]Daily compound interest Loop
我正在做一個項目,必須計算年初至今的每日交易復利,目前我只得到沒有利息的當前余額。 我相信我的問題與foreach循環有關,但我不確定在哪里出錯。 這是過去的日子,但是沒有利息申請或runTotal無法正常結轉。
public IEnumerable<DateTime> EachDay(DateTime from, DateTime thru)
{
for (var day = from.Date; day.Date <= thru.Date; day = day.AddDays(1))
yield return day;
}
public decimal PrincipalplusInterest()
{
DateTime startDate = new DateTime( DateTime.Now.Year, 1, 1);
DateTime endDate = startDate.AddYears(1);
int compoundingTimes = 12;
TimeSpan duration = endDate - startDate;
var numberOfDaysInYear = duration.Days;
decimal runningTotal = 0;
double interestRate = InterestRate;
foreach (DateTime day in EachDay(startDate, endDate))
{
decimal sumOfAnyTransactionToday = Transactions.Where(x => x.TransactionDate == day).Sum(x => x.Amount);
runningTotal = runningTotal + sumOfAnyTransactionToday;
double timePeriod = 1 / numberOfDaysInYear;
double rate = interestRate / compoundingTimes;
double total = System.Convert.ToDouble(runningTotal);
double principalAndInterest = total * Math.Pow((1 + rate), (compoundingTimes * timePeriod));
runningTotal = System.Convert.ToDecimal(principalAndInterest);
}
return runningTotal;
}
[DisplayName("Year to Date Interest")]
public decimal YrToDateInterest()
{
decimal interest = PrincipalplusInterest() - CurrentBalanceCalculation();
return interest;
}
您正在執行整數運算:
double timePeriod = 1 / numberOfDaysInYear;
numberOfDaysInYear
是一個整數,因此將1除以該值將始終返回0。
通過使值之一成為浮點數來計算浮點數:
double timePeriod = 1.0 / numberOfDaysInYear;
這可能是最簡單的解決方案。
同樣,如果您的交易包含時間成分,那么該語句將始終返回零,除非您碰巧恰好在午夜進行了交易。
Transactions.Where(x => x.TransactionDate == day).Sum(x => x.Amount);
要僅獲取日期,您需要獲取DateTime
對象的Date
組件:
Transactions.Where(x => x.TransactionDate.Date == day).Sum(x => x.Amount);
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