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[英]Looking for a Design pattern which can create different instances of a class with different interface implementations
[英]Design pattern for handling if else with different implementations
我有以下兩種類型的處理器
public interface IDefaultProcessor1
{
void Process(IProcess p);
}
public interface IDefaultProcessor2
{
T Process<T>(IProcess p);
}
public class DefaultProcessor : IDefaultProcessor1
{
public void Process(IProcess p)
{
try
{
foreach ...
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
throw;
}
}
}
public class AnotherProcessor : IDefaultProcessor2
{
public T Process<T>(IProcess p)
{
try
{
foreach ...
return p.Result()...
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
throw;
}
}
}
大多數實現代碼是完全相同的(錯誤檢查等),只是返回一個值。 有沒有一種模式可以解決這個問題?
就在這里。
在同一接口上定義兩個方法:
public interface IDefaultProcessor
{
void Process(IProcess p);
TResult Process<TResult>(IProcess p);
}
接着:
public class DefaultProcessor : IDefaultProcessor
{
public void Process(IProcess p)
{
DoProcess(p);
}
public TResult Process<TResult>(IProcess p)
{
object result = DoProcess(p);
return (TResult)result;
}
private object DoProcess(IProcess p)
{
try
{
foreach ...
return p.Result();
}
catch(Exception ex)
{
Console.WriteLine(ex.Message);
throw;
}
}
}
您可以通過多種方式執行此操作。 您要記住的一件事是,您不可能有一個帶有可選返回值的方法。 話雖如此,您可以嘗試以下方法之一:
public abstract class AbstractProcess<T>
{
public abstract T DoProcess();
public T Process()
{
//do your common tasks
return DoProcess();
}
}
public class Process1 : AbstractProcess<Process1>
{
public override Process1 DoProcess()
{
return new Process1();
}
}
public class Process2 : AbstractProcess<Process2>
{
public override Process2 DoProcess()
{
return null;
}
}
public interface IProcessor
{
T Process<T>();
void Process();
}
public class Processor : IProcessor
{
public void Process()
{
DoWork();
}
public T Process<T>()
{
return (T)DoWork();
}
public object DoWork()
{
// do your common tasks
}
}
public interface IProcessor
{
T Process<T>() where T : class;
}
public class Processor : IProcessor
{
public T Process<T>() where T : class
{
var result = (T)DoWork();
if (typeof(T) == typeof(Process2))
return result;
return null;
}
public object DoWork()
{
// do your common tasks
}
}
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