[英]Given two words, find whether they are in the same synset
對nltk來說還很新。 我正在嘗試找出當前正在解決的問題的解決方案:
謝謝。
還可以找到包含給定單詞的sysnet列表嗎?
是的 :
>>> from nltk.corpus import wordnet as wn
>>> auto, car = 'auto', 'car'
>>> wn.synsets(auto)
[Synset('car.n.01')]
>>> wn.synsets(car)
[Synset('car.n.01'), Synset('car.n.02'), Synset('car.n.03'), Synset('car.n.04'), Synset('cable_car.n.01')]
如果我們從wn.synsets(car)
每個同義詞wn.synsets(car)
查看引理,則會發現“ car”作為引理之一存在:
>>> for ss in wn.synsets(car):
... assert 'car' in ss.lemma_names()
...
>>> for ss in wn.synsets(car):
... print 'car' in ss.lemma_names(), ss.lemma_names()
...
True [u'car', u'auto', u'automobile', u'machine', u'motorcar']
True [u'car', u'railcar', u'railway_car', u'railroad_car']
True [u'car', u'gondola']
True [u'car', u'elevator_car']
True [u'cable_car', u'car']
注意:引理不是完全表面的單詞,另請參見Stemmers vs Lemmatizers ,您可能會發現此有用的https://github.com/alvations/pywsd/blob/master/pywsd/utils.py#L66 (免責聲明:無恥插頭)
給定兩個單詞w1和w2,有沒有一種方法可以找出它們是否在Wordnet數據庫中屬於相同的sysnet?
是的 :
>>> from nltk.corpus import wordnet as wn
>>> auto, car = 'auto', 'car'
>>> wn.synsets(auto)
[Synset('car.n.01')]
>>> wn.synsets(car)
[Synset('car.n.01'), Synset('car.n.02'), Synset('car.n.03'), Synset('car.n.04'), Synset('cable_car.n.01')]
>>> auto_ss = set(wn.synsets(auto))
>>> car_ss = set(wn.synsets(car))
>>> car_ss.intersection(auto_ss)
set([Synset('car.n.01')])
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