[英]Given two words, find whether they are in the same synset
对nltk来说还很新。 我正在尝试找出当前正在解决的问题的解决方案:
谢谢。
还可以找到包含给定单词的sysnet列表吗?
是的 :
>>> from nltk.corpus import wordnet as wn
>>> auto, car = 'auto', 'car'
>>> wn.synsets(auto)
[Synset('car.n.01')]
>>> wn.synsets(car)
[Synset('car.n.01'), Synset('car.n.02'), Synset('car.n.03'), Synset('car.n.04'), Synset('cable_car.n.01')]
如果我们从wn.synsets(car)
每个同义词wn.synsets(car)
查看引理,则会发现“ car”作为引理之一存在:
>>> for ss in wn.synsets(car):
... assert 'car' in ss.lemma_names()
...
>>> for ss in wn.synsets(car):
... print 'car' in ss.lemma_names(), ss.lemma_names()
...
True [u'car', u'auto', u'automobile', u'machine', u'motorcar']
True [u'car', u'railcar', u'railway_car', u'railroad_car']
True [u'car', u'gondola']
True [u'car', u'elevator_car']
True [u'cable_car', u'car']
注意:引理不是完全表面的单词,另请参见Stemmers vs Lemmatizers ,您可能会发现此有用的https://github.com/alvations/pywsd/blob/master/pywsd/utils.py#L66 (免责声明:无耻插头)
给定两个单词w1和w2,有没有一种方法可以找出它们是否在Wordnet数据库中属于相同的sysnet?
是的 :
>>> from nltk.corpus import wordnet as wn
>>> auto, car = 'auto', 'car'
>>> wn.synsets(auto)
[Synset('car.n.01')]
>>> wn.synsets(car)
[Synset('car.n.01'), Synset('car.n.02'), Synset('car.n.03'), Synset('car.n.04'), Synset('cable_car.n.01')]
>>> auto_ss = set(wn.synsets(auto))
>>> car_ss = set(wn.synsets(car))
>>> car_ss.intersection(auto_ss)
set([Synset('car.n.01')])
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