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[英]Is it possible to make Plotly choropleth use ISO 3166-1 alpha-2 country codes instead of ISO 3166-1 alpha-3 to map countries?
[英]Use PYCOUNTRY to convert ISO 3166-1 alpha-2 to Country Name
Python(和編碼新手)在這里。 我正在嘗試根據目錄中文件列表生成XML文件。 文件名的前兩個字母對應於新的字母國家/地區代碼,我也嘗試將其提取出來。
我的預期格式如下:
<ROOT>
<BASIC/>
<FULL>
<INFO>
<server>filname</server>
<country>country</country>
<region/>
</INFO>
</FULL>
</ROOT>
我似乎能夠生成XML文件,但是無法使用pycountry將兩位數的國家/地區代碼轉換為國家/地區。 有人可以建議一個可能的解決方案嗎? 對其余代碼的任何注釋也將有所幫助。
# -*- coding: utf-8 -*-
import lxml.etree as xml
import pycountry
import glob
import gettext
gettext.bindtextdomain('iso3166', pycountry.LOCALES_DIR)
_c = lambda t: gettext.dgettext('iso3166', t)
def createXML(outfile):
root = xml.Element("ROOT")
basic = xml.Element("BASIC")
full = xml.Element("FULL")
root.append(basic)
root.append(full)
# add file information
for filename in glob.glob("*.*"):
info = xml.Element("INFO")
server = xml.SubElement(info, "server")
server.text = filename
short = filename[:2]
country = xml.SubElement(info, "country")
def get_country(code):
return _c(pycountry.countries.get(alpha2=code).name)
country.text = get_country(short)
region = xml.SubElement(info, "region")
full.append(info)
print xml.tostring(root, pretty_print=True)
#save new XML
# tree = xml.ElementTree(root)
# with open(filename, "w") as fh:
# tree.write(fh)
#--------------------------------------------------------
if __name__ == "__main__":
createXML("info.xml")
感謝gbe的幫助! 它不是很漂亮,但是這里的代碼起作用了。
# -*- coding: utf-8 -*-
import lxml.etree as xml
import pycountry
import glob
import gettext
gettext.bindtextdomain('iso3166', pycountry.LOCALES_DIR)
_c = lambda t: gettext.dgettext('iso3166', t)
def createXML(outfile):
root = xml.Element("ROOT")
basic = xml.Element("BASIC")
full = xml.Element("FULL")
root.append(basic)
root.append(full)
# add file information
for filename in glob.glob("*.*"):
info = xml.Element("INFO")
server = xml.SubElement(info, "server")
server.text = filename
short = filename[:2].upper()
country = xml.SubElement(info, "country")
country.text = pycountry.countries.get(alpha2=short).name
region = xml.SubElement(info, "region")
full.append(info)
print xml.tostring(root, pretty_print=True)
#save new XML
# tree = xml.ElementTree(root)
# with open(filename, "w") as fh:
# tree.write(fh)
#--------------------------------------------------------
if __name__ == "__main__":
createXML("info.xml")
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