[英]Is it possible to insert a null value into a column where column data type is a double?
`enter code here`
private void btnSave_Click(object sender, RoutedEventArgs e)
{
GRepository<tblDEIPO_Primary> GR = new GRepository<tblDEIPO_Primary>();
tblDEIPO_Primary objDIE = new tblDEIPO_Primary();
if (txtid.Text == "")
{
objDIE.DIEPONo = txtDIEPO.Text;
objDIE.PoDate = dtpDeiPoDate.Text;
objDIE.Vendor = cmbVendor.Text;
objDIE.Remark = txtRemark.Text;
objDIE.TermsAndConditions = txtTermsAndCondition.Text;
objDIE.TaxType = cmbTaxtype.Text;
objDIE.Tax = Convert.ToDouble(txtTax.Text);
objDIE.TaxAmount = Convert.ToDouble(txtTaxAmount.Text);
objDIE.BonusPenalty = s;
if (chkBonus.IsChecked == true)
{
objDIE.BonusPenaltyAmount = Convert.ToDouble(txtBonus.Text);
}
else if (chkPenalty.IsChecked == true)
{
objDIE.BonusPenaltyAmount = Convert.ToDouble(txtPenalty.Text);
}
objDIE.DeiType = cmbDieType.Text;
objDIE.TypeofInjections = cmbTypeOfInjection.Text;
objDIE.Total =Convert.ToDouble( txtTotal.Text);
objDIE.TotalAmount =Convert.ToDouble(txtAmount.Text);
GR.Insert(objDIE);
GR.Save();}
當我單擊btnSave_Click按鈕時,發生時間錯誤,提示“輸入字符串格式不正確。” 在objDIE.Tax = Convert.ToDouble(txtTax.Text);中 因為該文本框中的insertin值為空白,所以該錯誤Plz幫助的任何解決方案。
> Blockquote
所以使用double.TryParse
double taxAmount= 0;
objDIE.TaxAmount = double.TryParse(txtTaxAmount.Text, out taxAmount) ? taxAmount: DbNull.Value;
您可以使用double.TryParse
來測試輸入的值是否為double。
您可以替換:
objDIE.TaxAmount = Convert.ToDouble(txtTaxAmount.Text);
通過
double num;
bool res = double.TryParse(txtTax.Text, out num);
if (res)
{
// String is a double.
objDIE.TaxAmount = num;
}
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