獲取同一列的總值多行和總共兩個不同的行（mysql查詢）

Question

我有一張表“記錄”[記錄] [1]

select typeofservice, 
       Coalesce(sum(incomecost,expensecost),0) 'incomecost,expensecost' 
from   records 
where  dateoftrans = '2016-11-22' 
group by typeofservice with rollup;

我希望能夠在第二張圖像上得到結果，這是我的查詢......所有這些交易都發生在一天。 請幫忙

https://i.stack.imgur.com/fLYav.png

Answer 1

以下查詢假定，對於給定類型的服務，您希望在收入成本總和超過費用成本之和時報告收入，反之亦然。 在每種情況下，收入和費用之間的差異在適當的列中報告，在備用列中報告NULL 。

SELECT typeofservice,
       CASE WHEN SUM(incomecost) - SUM(expensecost) > 0
            THEN SUM(incomecost) - SUM(expensecost)
            ELSE NULL END AS incomecost,
       CASE WHEN SUM(expensecost) - SUM(incomecost) > 0
            THEN SUM(expensecost) - SUM(incomecost)
            ELSE NULL END AS expensecost
FROM records
WHERE dateoftrans = '2016-11-22'
GROUP BY typeofservice
WITH ROLLUP

Answer 2

如果僅針對第二張圖像的結果，您可以嘗試sum(incomecost)和sum(expensecost)如下所示：

SELECT
    typeofservice,
    Coalesce(SUM(incomecost), 0) AS incomecost,
    Coalesce(SUM(expensecost), 0) AS expensecost
FROM records
GROUP BY typeofservice
WITH ROLLUP