[英]Grabbing part of a table from a database and displaying it on a website
我想從名為“ TKACONT”的數據庫中獲取表的一部分。
當用戶單擊執行tkakata()函數的按鈕時,我將抓取Firstname,Lastname和kata(點),然后將它們顯示在表中。
我在ID為displayrank
的<div>
顯示從最高點到最低點排序的表格。
這是代碼:
kataajax.js
function tkakata(){
var xmlHttp = createXmlHttpRequestObject();
function createXmlHttpRequestObject()
{
var xmlHttp;
if (window.XMLHttpRequest)
{
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlHttp = new XMLHttpRequest();
}
else {
// code for IE6, IE5
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
if(!xmlHttp)
alert("Something went wrong")
else
return xmlHttp
}
function process(){
if(xmlHttp.readyState==0 || xmlHttp.readyState==4)
{
xmlHttp.open("GET", "tkakatagrab.php", true)
xmlHttp.onreadystatechange = handleServerResponse;
xmlHttp.send(null);
}
else
{
setTimeout('process()',1000);
}
}
function handleServerResponse()
{
if(xmlHttp.readyState==4)
{
if(xmlHttp.status==200)
{
xmlResponse = xmlHttp.responseXML;
xmlDocumentElement = xmlResponse.documentElement;
message = xmlDocumentElement.firstChild.data;
document.getElementById("displayrank").innerHTML = message;
setTimeout('process()',1000);
}
else
{
alert("Database not connecting!")
}
}
}}
tkakatagrab.php
<?php
header('Content-Type: text/xml');
echo '<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>';
$con = mysqli_connect('MY_SERVER_IP','USERNAME','PASSWORD','TKACONT');
if(!$con){
die('Could not connect: ' . mysqli_error($con));
}
$sql="SELECT Firstname,Lastname,Kata FROM Contestant ORDER BY Kata DESC";
$result = mysqli_query($con,$sql);
echo '<response>';
echo "<table>
<tr>
<th>Points</th>
<th>Firstname</th>
<th>Lastname</th>";
//while loop right here
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['Kata'] . "</td>";
echo "<td>" . $row['Firstname'] . "</td>";
echo "<td>" . $row['Lastname'] . "</td>";
echo "</tr>";
}
echo "</table>";
echo '</response>';
mysqli_close($con);
?>
查詢的這一部分:
ORDER BY Kata DESC
將結果從最高到最低排序(即:DESCending),如果需要相反的順序(從最低到最高),則將DESC更改為ASC(ASCending)。
希望這可以幫助 :)
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