[英]print columns from python dictionary
我有一周以上的提交字典。 我想以每周日歷樣式的列打印出來。
{
'Fri':
['Commit: 04:15PM Move flex to mixin and do mobile-first queries\n',
'Commit: 03:52PM use padding to get the margins\n',
'Commit: 10:09AM Remove field_prepared_logo height\n',
'Commit: 03:15PM Add the final div to footer\n',
'Commit: 03:05PM Merge from redesign\n'],
'Thu':
['Commit: 10:25AM Design qa fixes on /clients page\n'],
'Tue': ['Commit: 09:40AM remove transform and tweak span placement in hamburger\n'],
'Wed': ['Commit: 02:19PM Change blockquote font and width\n']}
似乎使用numpy
是將其打印在列中的方法。 通過添加一些虛擬字符串,並將字典變成數組數組,我也能夠“使”列表均勻。 我正在努力的事情是如何將數組數組轉換為適當的numpy
數組。
“平衡”數組數組:
[
['Commit: 09:40AM remove transform and tweak span placement in hamburger\n', 'X', 'X', 'X', 'X']
['Commit: 02:19PM Change blockquote font and width\n', 'X', 'X', 'X', 'X']
['Commit: 04:15PM Move flex to mixin and do mobile-first queries\n', 'Commit: 03:52PM use padding to get the margins\n', 'Commit: 10:09AM Remove field_prepared_logo height\n', 'Commit: 03:15PM Add the final yeti to footer\n', 'Commit: 03:05PM Merge from p-redesign\n']
['Commit: 10:25AM Design qa fixes on /clients page\n', 'X', 'X', 'X', 'X']
]
我試過的
nump_array = numpy.array(array_of_arrays)
print(nump_array[:,0])
總是出錯IndexError: too many indices for array
。 我認為我需要做的是進入並將這些內部數組轉換為numpy數組,然后vstack
,但是我不清楚如何處理numpy。 我也想知道我是否應該從頭開始就不那么快就丟棄字典。
這是我正在尋找的簡化版本:
| Mon | Tue | Wed | Thu | Fri |
| 04:15 | 09:40 | 10:32| 04:12 | 11:00 |
| Move..|Do a ..|Add .. | Use ..| Change|
| 03:52 | | | | |
我認為您可以不使用numpy
而僅使用stdlib模塊來解決此問題!
from itertools import zip_longest
d = {'Fri': ['Commit: 04:15PM Move flex to mixin and do mobile-first queries\n',
'Commit: 03:52PM use padding to get the margins\n',
'Commit: 10:09AM Remove field_prepared_logo height\n',
'Commit: 03:15PM Add the final div to footer\n',
'Commit: 03:05PM Merge from redesign\n'],
'Thu': ['Commit: 10:25AM Design qa fixes on /clients page\n'],
'Tue': ['Commit: 09:40AM remove transform and tweak span placement in '
'hamburger\n'],
'Wed': ['Commit: 02:19PM Change blockquote font and width\n']}
for row in zip_longest(d['Tue'], d['Wed'], d['Thu'], d['Fri']):
print(row)
# ('Commit: 09:40AM remove transform and tweak span placement in hamburger\n', 'Commit: 02:19PM Change blockquote font and width\n', 'Commit: 10:25AM Design qa fixes on /clients page\n', 'Commit: 04:15PM Move flex to mixin and do mobile-first queries\n')
# (None, None, None, 'Commit: 03:52PM use padding to get the margins\n')
# (None, None, None, 'Commit: 10:09AM Remove field_prepared_logo height\n')
# (None, None, None, 'Commit: 03:15PM Add the final div to footer\n')
# (None, None, None, 'Commit: 03:05PM Merge from redesign\n')
zip_longest
消除了對數組進行“均勻分配”的需要 ……在沒有任何內容可放的地方,它只返回None
。 您也可以傳遞fillvalue=''
或類似的值來設置默認值。
您還可以使用有序字典來避免像我一樣手動指定日期的順序。
現在您已經有了單獨的行,剩下的就是漂亮打印中的練習。 textwrap
模塊可能是您的朋友。
編輯:這花了點功夫,但是這也是漂亮的印刷品
maxwidth = (80//len(d)) - 1 # set this to whatever value you want
wrapper = textwrap.TextWrapper(width=maxwidth, subsequent_indent=' ')
wrapped_commits = {k: [wrapper.wrap(commit) for commit in v] for k, v in d.items()}
justified_commits = {k: [line.ljust(maxwidth) for commit in v for line in commit] for k, v in wrapped_commits.items()}
for l in zip_longest(justified_commits['Tue'], justified_commits['Wed'], justified_commits['Thu'], justified_commits['Fri'], fillvalue=' '*maxwidth):
print(' '.join(l))
這是輸出:
Commit: 09:40AM Commit: 02:19PM Commit: 10:25AM Commit: 04:15PM
remove transform Change blockquote Design qa fixes on Move flex to mixin
and tweak span font and width /clients page and do mobile-
placement in first queries
hamburger Commit: 03:52PM use
padding to get the
margins
Commit: 10:09AM
Remove field_prepa
red_logo height
Commit: 03:15PM Add
the final div to
footer
Commit: 03:05PM
Merge from
redesign
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