[英]Generics and wildcards with collections in Java
在使用AssertJ的測試類中,我的代碼類似於以下內容:
public void someTest() {
assertThat(getNames()).has(sameNamesAs(getExpectedNames()));
assertThat(getNames()).doesNotHave(sameNamesAs(getOtherNames()));
}
private List<String> getNames() {
return null;
}
private List<String> getExpectedNames() {
return null;
}
private List<String> getOtherNames() {
return null;
}
private Condition<List<String>> sameNamesAs(List<String> rhs) {
return new Condition<List<String>>("same names as " + rhs) {
@Override
public boolean matches(final List<String> lhs) {
return lhs.containsAll(rhs) && rhs.containsAll(lhs);
}
};
}
我對has
和doesNotHave
的調用出現了編譯錯誤:
has/doesNotHave
(org.assertj.core.api.Condition<? super java.util.List<? extends java.lang.String>>)
in AbstractListAssert cannot be applied
to
(org.assertj.core.api.Condition<java.util.List<java.lang.String>>).
我是新來的Java,我不明白的問題: java.util.List
是一個超級型java.util.List
和java.lang.String
延伸java.lang.String
,不是嗎?
在你的情況下, has
和doesNotHave
方法采用Condition<? super List<? extends T>
Condition<? super List<? extends T>
Condition<? super List<? extends T>
條件,而不是Condition<? super List<T>>
當您從Condition<List<T>> sameNamesAs
方法返回時, Condition<? super List<T>>
。
您需要Condition<List<? extends String>>
的實例 Condition<List<? extends String>>
type(它是原始類型Condition<? super List<? extends String>>
的子類):
private Condition<List<? extends String>> sameNamesAs(List<String> rhs) {
return new Condition<List<? extends String>>("same names as " + rhs) { ... };
}
我嘗試使用以下代碼段來說明這一點:
List<String> list = getNames();
// ELEMENT = String, ACTUAL = List<? extends ELEMENT>
ListAssert<String> assertThat = assertThat(list);
// by the signature, we have to pass Condition<? super ELEMENT> or Condition<? super ACTUAL>
// Condition<? super ACTUAL> = Condition<? super List<? extends String>>
Condition<List<? extends String>> condition = sameNamesAs(list);
// Condition<List<? extends String>> extends Condition<? super List<? extends String>>
assertThat.has(condition);
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