简体   繁体   English

带有Java集合的泛型和通配符

[英]Generics and wildcards with collections in Java

In a test class using AssertJ, I have code similar to the following: 在使用AssertJ的测试类中,我的代码类似于以下内容:

public void someTest() {
    assertThat(getNames()).has(sameNamesAs(getExpectedNames()));
    assertThat(getNames()).doesNotHave(sameNamesAs(getOtherNames()));
}

private List<String> getNames() {
    return null;
}
private List<String> getExpectedNames() {
    return null;
}
private List<String> getOtherNames() {
    return null;
}

private Condition<List<String>> sameNamesAs(List<String> rhs) {
    return new Condition<List<String>>("same names as " + rhs) {
        @Override
        public boolean matches(final List<String> lhs) {
            return lhs.containsAll(rhs) && rhs.containsAll(lhs);
        }
    };
}

I get a compilation error on the calls to has and doesNotHave : 我对hasdoesNotHave的调用出现了编译错误:

has/doesNotHave
(org.assertj.core.api.Condition<? super java.util.List<? extends java.lang.String>>)
in AbstractListAssert cannot be applied
to
(org.assertj.core.api.Condition<java.util.List<java.lang.String>>).

I'm new to Java and I don't understand the problem: java.util.List is a super-type of java.util.List and java.lang.String extends java.lang.String , don't they? 我是新来的Java,我不明白的问题: java.util.List是一个超级型java.util.Listjava.lang.String延伸java.lang.String ,不是吗?

In your case, the has and doesNotHave methods take a Condition<? super List<? extends T> 在你的情况下, hasdoesNotHave方法采用Condition<? super List<? extends T> Condition<? super List<? extends T> Condition<? super List<? extends T> condition, not a Condition<? super List<T>> Condition<? super List<? extends T>条件,而不是Condition<? super List<T>> Condition<? super List<T>> as you are returning from your Condition<List<T>> sameNamesAs method. 当您从Condition<List<T>> sameNamesAs方法返回时, Condition<? super List<T>>

You need an instance of the Condition<List<? extends String>> 您需要Condition<List<? extends String>>的实例 Condition<List<? extends String>> type (it's a subclass of the original type Condition<? super List<? extends String>> ): Condition<List<? extends String>> type(它是原始类型Condition<? super List<? extends String>>的子类):

private Condition<List<? extends String>> sameNamesAs(List<String> rhs) {
    return new Condition<List<? extends String>>("same names as " + rhs) { ... };
}

I tried to illustrate this with the following snippet: 我尝试使用以下代码段来说明这一点:

List<String> list = getNames();

// ELEMENT = String, ACTUAL = List<? extends ELEMENT>
ListAssert<String> assertThat = assertThat(list);

// by the signature, we have to pass Condition<? super ELEMENT> or Condition<? super ACTUAL>
// Condition<? super ACTUAL> = Condition<? super List<? extends String>>
Condition<List<? extends String>> condition = sameNamesAs(list);

// Condition<List<? extends String>> extends Condition<? super List<? extends String>>
assertThat.has(condition);

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM