拼接或刪除JSON數組中的元素列表

Question

我從REST API這樣獲得了JSON Array Output，我正在使用ng-repeat在HTML上顯示此項目。

var searchresponse = [{
    "items": [{
        "employeeId": "ABC",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "DEF",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "NPK",
        "type": "D",
        "alive": "Yes"

    }, {
        "employeeId": "PKN",
        "type": "A",
        "alive": "Yes"
    }],
    "more": false
}];

當用戶嘗試使用selectall / single select刪除時，我正在調用REST API來從db中刪除員工ID。 一旦獲得成功的響應，我計划拼接/刪除用戶從VIEW中選擇的值。 我想刪除以下employeeid及其類型，將其從搜索響應中刪除

 var data1=["ABC","NPK"];

數據1中具有相應詳細信息的任何內容均應從搜索響應中刪除

Answer 1

您需要做的就是使用splice方法從employeeId在data1 items數組中消除每個項目。

參考

• 拼接方法。

• indexOf方法

 var searchresponse = [{ "items": [{ "employeeId": "ABC", "type": "D", "alive": "Yes" }, { "employeeId": "DEF", "type": "D", "alive": "Yes" }, { "employeeId": "NPK", "type": "D", "alive": "Yes" }, { "employeeId": "PKN", "type": "A", "alive": "Yes" }], "more": false }]; var data1=["ABC","DEF"]; var items=searchresponse[0].items; var i=items.length; while (i--) { if(data1.indexOf(items[i].employeeId)!=-1){ items.splice(i,1); } } console.log(searchresponse[0].items);