實體框架空指針引用異常

Question

我有兩個表之間的關系

第一表： 用戶

Id | Name | 

第二張表： 套餐

Id | UserSenderId | UserReceiverId

我將Entity Framework與.Net Framework 3.5結合使用，但問題是Entity Framework正在創建兩個引用UserReference1和UserReference但UserReference1始終為null。 如果我不包括這樣的User表：

db.Packages.Include("User")

那么UserReference也為null。

我真的沒有這個問題的主意，使用多個外鍵指向同一主鍵是否存在問題？

編輯1：

在用戶參考Package部分類：

[global::System.Data.Objects.DataClasses.EdmRelationshipNavigationPropertyAttribute("Tema4Model", "FK_Package_User_Receiver", "User")]
[global::System.CodeDom.Compiler.GeneratedCode("System.Data.Entity.Design.EntityClassGenerator", "4.0.0.0")]
[global::System.Xml.Serialization.XmlIgnoreAttribute()]
[global::System.Xml.Serialization.SoapIgnoreAttribute()]
[global::System.Runtime.Serialization.DataMemberAttribute()]
public User User
{
    get
    {
        return ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.GetRelatedReference<User>("Tema4Model.FK_Package_User_Receiver", "User").Value;
    }
    set
    {
        ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.GetRelatedReference<User>("Tema4Model.FK_Package_User_Receiver", "User").Value = value;
    }
}

/// <summary>
/// There are no comments for User in the schema.
/// </summary>
[global::System.ComponentModel.BrowsableAttribute(false)]
[global::System.CodeDom.Compiler.GeneratedCode("System.Data.Entity.Design.EntityClassGenerator", "4.0.0.0")]
[global::System.Runtime.Serialization.DataMemberAttribute()]
public global::System.Data.Objects.DataClasses.EntityReference<User> UserReference
{
    get
    {
        return ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.GetRelatedReference<User>("Tema4Model.FK_Package_User_Receiver", "User");
    }
    set
    {
        if ((value != null))
        {
            ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.InitializeRelatedReference<User>("Tema4Model.FK_Package_User_Receiver", "User", value);
        }
    }
}

/// <summary>
/// There are no comments for User1 in the schema.
/// </summary>
[global::System.Data.Objects.DataClasses.EdmRelationshipNavigationPropertyAttribute("Tema4Model", "FK_Package_User_Sender", "User")]
[global::System.CodeDom.Compiler.GeneratedCode("System.Data.Entity.Design.EntityClassGenerator", "4.0.0.0")]
[global::System.Xml.Serialization.XmlIgnoreAttribute()]
[global::System.Xml.Serialization.SoapIgnoreAttribute()]
[global::System.Runtime.Serialization.DataMemberAttribute()]
public User User1
{
    get
    {
        return ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.GetRelatedReference<User>("Tema4Model.FK_Package_User_Sender", "User").Value;
    }
    set
    {
        ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.GetRelatedReference<User>("Tema4Model.FK_Package_User_Sender", "User").Value = value;
    }
}

/// <summary>
/// There are no comments for User1 in the schema.
/// </summary>
[global::System.ComponentModel.BrowsableAttribute(false)]
[global::System.CodeDom.Compiler.GeneratedCode("System.Data.Entity.Design.EntityClassGenerator", "4.0.0.0")]
[global::System.Runtime.Serialization.DataMemberAttribute()]
public global::System.Data.Objects.DataClasses.EntityReference<User> User1Reference
{
    get
    {
        return ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.GetRelatedReference<User>("Tema4Model.FK_Package_User_Sender", "User");
    }
    set
    {
        if ((value != null))
        {
            ((global::System.Data.Objects.DataClasses.IEntityWithRelationships)(this)).RelationshipManager.InitializeRelatedReference<User>("Tema4Model.FK_Package_User_Sender", "User", value);
        }
    }
}

任何幫助表示贊賞，謝謝！

Answer 1

嘗試db.Packages.Include("User").Include("User1")